按另一个表中另外两个列的计数总和的顺序获取表行答案

【问题标题】：Getting table rows in order of sum of count of two another columns from another table按另一个表中另外两个列的计数总和的顺序获取表行
【发布时间】：2015-12-14 07:30:56
【问题描述】：

我有 3 个 MYSQL 表，它们是：

发布

mysql> DESCRIBE `posts`;
+------------------+------------------+------+-----+---------+----------------+
| Field            | Type             | Null | Key | Default | Extra          |
+------------------+------------------+------+-----+---------+----------------+
| post_id          | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| post_details     | varchar(11)      | NO   |     | NULL    |                |                |
+------------------+------------------+------+-----+---------+----------------+

喜欢

mysql> DESCRIBE `likes`;
+------------------+------------------+------+-----+---------+----------------+
| Field            | Type             | Null | Key | Default | Extra          |
+------------------+------------------+------+-----+---------+----------------+
| id               | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| post_id          | int(11)          | NO   |     | NULL    |                |
| user_id          | int(11)          | NO   |     | NULL    |                |                |
+------------------+------------------+------+-----+---------+----------------+

mysql> DESCRIBE `comments`;
+------------------+------------------+------+-----+---------+----------------+
| Field            | Type             | Null | Key | Default | Extra          |
+------------------+------------------+------+-----+---------+----------------+
| id               | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| post_id          | int(11)          | NO   |     | NULL    |                |
| user_id          | int(11)          | NO   |     | NULL    |                |                |
+------------------+------------------+------+-----+---------+----------------+

在第 2 和第 3 表中，我正在存储帖子的喜欢和 cmets（第 1 表）。现在，我想按喜欢和 cmets 的总和的降序获取帖子。即，帖子将按照最大点赞数 + cmets 到最小数量的顺序排列。请帮助我获得正确的结果并提前感谢。

【问题讨论】：

标签： mysql

【解决方案1】：

SELECT posts.post_id, post_details,
    ((SELECT(COUNT(id) FROM comments WHERE comments.post_id = posts.post_id)) + (SELECT(COUNT(id) FROM likes WHERE likes.post_id = posts.post_id))) AS weight
FROM posts
ORDER BY weight DESC

不使用变量，您可以使用嵌套选择

【讨论】：

是的，用额外的括号纠正一点语法错误，它开始工作。感谢您的帮助。

【解决方案2】：

试试：

@likes = SELECT COUNT(id) FROM likes;
@comments = SELECT COUNT(id) FROM comments;
SELECT post_id, (@likes + @comments) AS TotalStats  FROM posts GROUP BY post_id ORDER BY TotalStats DESC;

【讨论】：