【发布时间】：2019-05-15 11:45:18
【问题描述】：
我有一个程序可以执行不同类型的统计分析。我想为每种类型的分析定义一个子命令。父命令将是程序的主要入口点。当我的子命令具有相同名称的选项时，我收到一条错误消息，提示“选项应仅指定一次”。问题似乎是我如何调用子命令。在下面的示例中，input1 和 input2 工作正常。当我尝试同时使用两个子命令 (input3) 时，我收到一条错误消息。
下面的代码演示了这个问题。如果输入包含两个子命令（即 input3），我会收到错误消息“索引 0 () 处的选项 '-id' 应仅指定一次”。
如何像在 input3 中一样同时调用两个子命令？
import picocli.CommandLine;
import java.util.concurrent.Callable;
@CommandLine.Command(name = "myprogram", subcommands = {TestCase.FrequencyCommand.class, TestCase.HistogramCommand.class})
public class TestCase implements Callable<Void> {
public TestCase(){
}
public Void call() {
System.out.println("Main program called");
return null;
}
public static void main(String[] args){
String[] input1 = {"frequency", "-id", "1001", "-table", "ex1"};
String[] input2 = {"histogram", "-id", "1002", "-table", "ex5" };
String[] input3 = {"frequency", "-id", "1001", "-table", "ex1", "histogram", "-id", "1002", "-table", "ex5" };
CommandLine commandLine = new CommandLine(new TestCase());
System.out.println("==Test1==");
commandLine.execute(input1);
System.out.println();
System.out.println("==Test2==");
commandLine.execute(input2);
System.out.println();
System.out.println("==Test3==");
commandLine.execute(input3);
System.out.println();
}
@CommandLine.Command(name = "frequency", description = "Frequency analysis.")
static class FrequencyCommand implements Callable<Void> {
@CommandLine.Option(names = {"-id"}, arity = "1..*", description = "Unique case identifier")
public String id;
@CommandLine.Option(names = "-table", arity = "1..*", description = "Database table")
public String table;
public FrequencyCommand(){
}
public Void call() {
System.out.println("Frequency");
System.out.println("ID = " + id);
System.out.println("Table = " + table);
return null;
}
}
@CommandLine.Command(name = "histogram", description = "Histogram plot.")
static class HistogramCommand implements Callable<Void> {
@CommandLine.Option(names = {"-id"}, arity = "1..*", description = "Unique case identifier")
public String id;
@CommandLine.Option(names = "-table", arity = "1..*", description = "Database table")
public String table;
public HistogramCommand(){
}
public Void call() {
System.out.println("Histogram");
System.out.println("ID = " + id);
System.out.println("Table = " + table);
return null;
}
}
}
我希望看到的输出是：
==测试1==
频率
ID = 1001
表 = ex1
==测试2==
直方图
ID = 1002
表 = ex5
==测试3==
频率
ID = 1001
表 = ex1
直方图
ID = 1002
表 = ex5
【问题讨论】：
标签： picocli