Jenkins、Groovy 和正则表达式

Question

我对使用 groovy 很陌生。尤其是 Jenkins+Groovy+Pipelines。

我有一个可以不时更改的字符串变量，我想应用一个正则表达式来适应字符串可能返回的 2 或 3 个可能的结果。

在我的 groovy 代码中：

r = "Some text that will always end in either running, stopped, starting." def regex = ~/(.*)running(.*)/ assert regex.matches(r)

但我在 jenkins 输出中收到错误：

hudson.remoting.ProxyException：groovy.lang.MissingMethodException：没有方法签名：java.util.regex.Pattern.matches() 适用于参数类型：(java.lang.String)

更新： 我能够在我正在创建的管道作业中创建一个非常漂亮的 jenking groovy while 循环，以使用此处的正则表达式信息和不同帖子 (do .. while() in Groovy with inputStream?) 中的提示等待远程进程。

            while({
                def r = sh returnStdout: true, script: 'ssh "Insert your remote ssh command that returns text'
                println "Process still running.  Waiting on Stop"
                println "Status returned: $r"
                r =~ /running|starting|partial/
            }());

Answer 1

直截了当：

String r = "Some text that will always end in either running, stopped, starting."
assert r =~ /(.*)running(.*)/

Answer 2

如果您只在此处使用此正则表达式，您可以尝试以下操作：

r = "Some text that will always end in either running, stopped, starting."
assert r ==~ /(.*)(running|stopped|starting)\.?$/, "String should end with either running, started or stopped" 

解释：

(.*) - matches anything
(running|stopped|starting) - matches either running, stopped or starting
\.? - optionally end with a dot expect zero or one occurrence of a dot, but you need to escape it, because the dot is a regex special character
$ - end of the line, so nothing should come after

==~ 运算符是常规的 binary match operator。如果匹配则返回true，否则返回false

在正则表达式 101 上查看 this example

Answer 3

matches 没有收到字符串。

试试

Pattern.compile("your-regex").matcher("string-to-check").find()