【发布时间】:2014-04-09 15:47:41
【问题描述】:
正如我的标题所说,我的服务器端应用程序有问题,
我有一个带有 getter 和 setter 方法的类,称为 LocationBean
public class LocationBean {
private String location;
private String ReaderID;
public String getLocation () {
return location;
}
public String getReaderID () {
return ReaderID;
}
public void setLocation (String newlocation) {
location = newlocation;
}
public void setReaderID (String newReaderID) {
ReaderID = newReaderID;
}
}
然后我的主 servlet 类称为 getlocation
package location;
import java.io.*;
import java.util.List;
import javax.servlet.*;
import javax.servlet.http.*;
import org.json.simple.JSONObject;
public class getlocation extends HttpServlet {
String ReaderID;
String locs;
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
{
ReaderID = request.getParameter("readerid");
locs = LocationDAO.getloc(ReaderID);
JSONObject loc = new JSONObject();
loc.put("Location", locs);
response.setContentType("application/json");
PrintWriter out = response.getWriter();
out.print(loc);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
{
}
}
最后是我的 DAO 类,名为 LocationDAO
package location;
import java.sql.*;
public class LocationDAO {
public static String getloc(String ReaderID) {
// TODO Auto-generated method stub
Connection conn =null; // Create connection object
Statement stmt = null;
ResultSet rs1 = null;
String database = ""; // Name of database
String user = ""; //
String password = "";
String url = "jdbc:mysql://:3306/" + database;
String Location = null;
String Rid = ReaderID;
try{
Class.forName("com.mysql.jdbc.Driver").newInstance();
} catch(Exception e) {
System.err.println(e);
}
// connecting to database
try {
conn = DriverManager.getConnection(url, user, password);
} catch(SQLException se) {
System.err.println(se);
}
// Create select statement and execute it
try {
String selectSQL = "select Location from `LocationTable` where ReaderID ='"+Rid + "'";
stmt = conn.createStatement();
rs1 = stmt.executeQuery(selectSQL);
// Retrieve the results
if(rs1.next()) {
Location = rs1.getString("Location");
}
conn.close();
} catch(SQLException se) {
System.err.println(se);
}
return Location;
}
}
我已删除数据库详细信息,例如 url 密码等,因为它托管在我自己的服务器上,不希望将其发布在互联网上。所以当数据发送到这里时他们的问题是我收到这个错误消息
HTTP 状态 500 -
输入异常报告
消息
描述服务器遇到了一个内部错误,导致它无法完成这个请求。
异常
java.lang.NullPointerException
location.LocationDAO.getloc(LocationDAO.java:39)
location.getlocation.doGet(getlocation.java:23)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
如果有人能提供帮助,将不胜感激
【问题讨论】:
-
我已将 cmets 添加到代码中,堆栈跟踪位于与其相关的代码行下方
-
那么您检查 rs1 是否为空?这就是大神创建调试器的原因。
-
这不是在应用服务器中获取连接的正确方法。您必须配置数据源并从您的应用中查找:tomcat.apache.org/tomcat-6.0-doc/…
-
iv 更改了代码以测试连接是否有效,作为一个独立的类,它可以正常工作并返回我需要的位置,我遇到的问题是将此方法添加到我想返回的 servlet位置返回给客户端。