在 iOS 模拟器上测试虚假的当前位置不起作用

Question

我一直试图在 iOS 模拟器中伪造我的位置，但我一直在阅读的方法不起作用。我已经使用调试器设置了我的假位置，并在 Debug->Location->Custom Location 中创建了一个自定义位置，但我仍然记录 0.000 0.000 的经纬度。 我正在使用此代码查找当前位置。

- (IBAction)currentLocationButtonPressed:(UIButton *)sender
{
    //Search for pubs and bars in current location.
    //Push to tableViewController
    NSLog(@"current location Pressed.");

    locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move
    locationManager.desiredAccuracy = kCLLocationAccuracyBest; // Best accuracy
    [locationManager startUpdatingLocation];
    NSLog(@"%@",[self deviceLocation]);
}

- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
    NSLog(@"didUpdateToLocation: %@", newLocation);
    CLLocation *currentLocation = newLocation;

    if (currentLocation != nil) {
        NSLog(@"Latitude: %f Longitude: %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);
    }
}

- (NSString *)deviceLocation {
    return [NSString stringWithFormat:@"latitude: %f longitude: %f", locationManager.location.coordinate.latitude, locationManager.location.coordinate.longitude];
}

委托已设置，我正在请求授权。

- (void)viewDidLoad {
    [super viewDidLoad];

    searchLocationTextField.delegate = self;
    locationManager.delegate = self;
    locationManager = [[CLLocationManager alloc]init];
    [locationManager requestWhenInUseAuthorization];  // For foreground access
    [locationManager requestAlwaysAuthorization]; // For background access

}

Answer 1

在分配后将 locationManager 委托设置为。

locationManager = [[CLLocationManager alloc]init];
locationManager.delegate = self;

locationManager:didUpdateToLocation:fromLocation: 委托方法已弃用，请改用locationManager:didUpdateLocations:。

-(void) locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
    CLLocation *currentLocation = [locations lastObject];

    NSLog(@"Latitude: %f Longitude: %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);
}