如何在运行时使用反射构建这个 c#“表达式”？

Question

直到今天，我还没有找到一篇关于表达式的好文章——以及如何查看 C# lambda 语句并说“哦，那是废话”......所以，如果你知道一篇好文章，我作为一个答案也很感激。

解释问题的代码示例

所以...给定以下 c# 代码：

public class SomeClass<T>
{
    public TResult SomeMethod<TResult>(Expression<Func<T, TResult>> expression)
    {
        // This is just an example... don't get hung up on this :)
        return default(TResult);
    }
}

public class Person
{
    public string FirstName { get; set; }

    public string LastName { get; set; }
}

我该怎么做...

var blah = new SomeClass<Person>();

blah.SomeMethod(p => p.FirstName);

在运行时（使用反射）？

我期望的答案

我有点期待这样的事情......但我确定我对我的表达方式的选择很不满意。

// By the way, these values are being passed to me... so you
// can't change this part of the question :)
Type personType = typeof(Person);
string propertyName = "FirstName";

// THIS CODE BELOW IS OBVIOUSLY WRONG, BUT YOU GET THE IDEA OF
// WHAT I HOPE TO DO... THIS LINE OF CODE BELOW IS **ALL** I'M
// ASKING HOW TO DO :)
var expression = Expression.MakeUnary(ExpressionType.Lambda,
    Expression.Property(Expression.Parameter(personType, "p"),
    propertyName), typeof(string));

blah.SomeMethod(expression);

Answer 1

试试这个：

var functorParam = Expression.Parameter(typeof(Person));
var lambda = Expression.Lambda(
    Expression.Property(functorParam, typeof(Person).GetProperty("FirstName"))
,   functorParam /* <<= EDIT #1 */
);
blah.SomeMethod((Expression<Func<Person,string>>)lambda); /* EDIT #2 */

Answer 2

ExpressionBuilder 是要走的路。