使用 vimeo api 时收到错误 303 无效签名

Question

.. 我遇到了无效签名错误。有人可以帮我解决这个问题吗？我错过了什么吗？ Oauth_token 是我授权后得到的访问令牌

网址：vimeo.com/api/rest/v2?method=vimeo.oauth.checkAccessToken

基本字符串： GET&http%3A%2F%2Fvimeo.com%2Fapi%2Frest%2Fv2&method%3Dvimeo.oauth.checkAccessToken%26oauth_consumer_key%3D763ebd960af20c4844be38d388299f62%26oauth_nonce%3D-5297335925725406200%26oauth_signature_method%3DHMAC-SHA1%26oauth_timestamp%3D1329134906%26oauth_token%3Da61b496a94ebdaa151f1b757bdd54ad7%26oauth_version%3D1. 0

HEADER:OAuth oauth_consumer_key="763ebd960af20c4844be38d388299f62", oauth_nonce="-5297335925725406200", oauth_signature="0xBOoOtHG%2BoiAImx3no0bUTTFeU%3D", oauth_signature_method="HMAC-SHA1", oauth_timestamp="1329134906", oauth_token="a61b496a94ebdaa151f1b757bdd54ad7", oauth_version ="1.0" 

Answer 1

不知道您是否仍然遇到此问题，但您可以尝试使用scribe。我一直在为 vimeo 开发一个应用程序，并且严重依赖 Scribe 来签署和发送我的请求。以下是身份验证、签名和发送请求的示例：

  private static OAuthService service;
  private static Token accessToken;
  private static String newline = System.getProperty("line.separator");

  public static void main(String[] args) throws Exception {
    // Replace these with your own api key and secret

    String apiKey = "YOUR_API_KEY"; //Give your own API Key
    String apiSecret = "YOUR_API_SECRET"; //Give your own API Secret
    String vimeoAPIURL = "http://vimeo.com/api/rest/v2";
    service = new ServiceBuilder().provider(VimeoApi.class).apiKey(apiKey).apiSecret(apiSecret).build();

    OAuthRequest request;
    Response response;

    accessToken = new Token("AN_INVALID_TOKEN_WILL", "REQUIRE_GETTING_A_NEW_ONE"); //Copy the new token you get here

    accessToken = checkToken(vimeoAPIURL, accessToken, service);
    if (accessToken == null) {
      return;
    }
 }

  /**
  * Checks the token to make sure it's still valid. If not, it pops up a dialog asking the user to
  * authenticate.
  */
  private static Token checkToken(String vimeoAPIURL, Token vimeoToken, OAuthService vimeoService) {
    if (vimeoToken == null) {
      vimeoToken = getNewToken(vimeoService);
    } else {
      OAuthRequest request = new OAuthRequest(Verb.GET, vimeoAPIURL);
      request.addQuerystringParameter("method", "vimeo.oauth.checkAccessToken");
      Response response = signAndSendToVimeo(request, "checkAccessToken", true);
      if (response.isSuccessful()
              && (response.getCode() != 200 || response.getBody().contains("<err code=\"302\"")
              || response.getBody().contains("<err code=\"401\""))) {
        vimeoToken = getNewToken(vimeoService);
      }
    }
    return vimeoToken;
  }

  /**
  * Gets authorization URL, pops up a dialog asking the user to authenticate with the url and the user
  * returns the authorization code
  *
  * @param service
  * @return
  */
  private static Token getNewToken(OAuthService service) {
    // Obtain the Authorization URL
    Token requestToken = service.getRequestToken();
    String authorizationUrl = service.getAuthorizationUrl(requestToken);
    do {
      String code = JOptionPane.showInputDialog("The token for the account (whatever)" + newline
              + "is either not set or is no longer valid." + newline
              + "Please go to the URL below and authorize this application." + newline
              + "Paste the code you're given on top of the URL here and click \'OK\'" + newline
              + "(click the 'x' or input the letter 'q' to cancel." + newline
              + "If you input an invalid code, I'll keep popping up).", authorizationUrl + "&permission=delete");
      if (code == null) {
        return null;
      }
      Verifier verifier = new Verifier(code);
      // Trade the Request Token and Verfier for the Access Token
      System.out.println("Trading the Request Token for an Access Token...");
      try {
        Token token = service.getAccessToken(requestToken, verifier);
        System.out.println(token); //Use this output to copy the token into your code so you don't have to do this over and over.
        return token;
      } catch (OAuthException ex) {
        int choice = JOptionPane.showConfirmDialog(null, "There was an OAuthException" + newline
                + ex + newline
                + "Would you like to try again?", "OAuthException", JOptionPane.YES_NO_OPTION);
        if (choice == JOptionPane.NO_OPTION) {
          break;
        }
      }
    } while (true);
    return null;
  }

  /**
  * Signs the request and sends it. Returns the response.
  *
  * @param request
  * @return response
  */
  public static Response signAndSendToVimeo(OAuthRequest request) throws org.scribe.exceptions.OAuthException {
    service.signRequest(accessToken, request);
    Response response = request.send();
    return response;
  }

Answer 2

伙计们，我有几乎类似的问题。

我正在处理基本呼叫，一切正常。但我意识到基本只允许您查询 60 个视频。每页 20 个视频。下面是我尝试使用 basic 实现分页的链接，但代码仅适用于三个页面，即 30 个视频。

http://projects.tk-fn.com/controls/Vimeo/BKBVideoPage-Backup.html

然后我尝试了允许每页 50 个和无限视频的高级 api。 我能够完成所有 OAuth 实现，但现在的问题是当我将它放在浏览器中时 url 工作正常，但当我尝试进行 JSONP ajax 调用时它不起作用。 :(

http://projects.tk-fn.com/controls/Vimeo/OAuthSimple.html

对于那些知道的人。 OAuth 接受所有必需的参数，例如 Consumer_Key、Secret、NONE（随机字符串）、timestamp、oauth_signature（使用整个url创建）。

我找到了一个名为 Simple OAuth 的类并使用了它。

每次都刷新页面以获取正确的网址。 URL 不能多次使用。 Vimeo 将期望每个请求都有新的 url。