反序列化复杂对象中的xml答案

【问题标题】：deserialize xml in complex object反序列化复杂对象中的xml
【发布时间】：2012-03-26 11:00:41
【问题描述】：

我不明白为什么 object 为空：

        WebClient browse = new WebClient();
        StreamReader res = new StreamReader(browse.OpenRead("http://ws.audioscrobbler.com/2.0/?method=track.getinfo&api_key=b25b959554ed76058ac220b7b2e0a026&artist=cher&track=believe"));
        string result = res.ReadToEnd();

        XmlDocument xmltrackinfo = new XmlDocument();
        xmltrackinfo.InnerXml = result;



        XmlRootAttribute xRoot = new XmlRootAttribute();
        xRoot.ElementName = "lfm";
        xRoot.IsNullable = true;

        XmlSerializer xs = new XmlSerializer(typeof(fm), xRoot);

        fm rez = (fm) xs.Deserialize(new MemoryStream(Encoding.UTF8.GetBytes(result)));

对象模型：

[Serializable()]
[XmlRoot(ElementName = "lfm", IsNullable = true)]
public class fm
{
    [XmlElement("lfm")]
    public Track lfm { get; set; }
}

[Serializable()]
[XmlRoot(ElementName = "artist", IsNullable = true)]
public class artist
{
    public string name { get; set; }
    public string mbid { get; set; }
    public string url { get; set; }
}

[Serializable()]
[XmlRoot(ElementName = "album", IsNullable = true)]
public class album
{
    public string artist { get; set; }
    public string title { get; set; }
    public string mbid { get; set; }
    public string url { get; set; }
    public List<string> image { get; set; }
}

[Serializable()]
[XmlRoot(ElementName = "tag", IsNullable = true)]
public class tag
{
    public string name { get; set; }
    public string url { get; set; }

}

[Serializable()]
[XmlRoot(ElementName = "wiki", IsNullable = true)]
public class wiki
{
    public string summary { get; set; }
    public string content { get; set; }
}

[Serializable()]
[XmlRoot(ElementName = "track", IsNullable = true)]
public class Track
{
    public string id { get; set; }
    public string name { get; set; }
    public string mbid { get; set; }
    public string url { get; set; }
    public string duration { get; set; }
    public string streamable { get; set; }
    public string listeners { get; set; }
    public string playcount { get; set; }
    public artist artist { get; set; }
    public album album { get; set; }
    public List<tag> toptags { get; set; }
    public wiki wiki { get; set; }

}

和 XML：

http://ws.audioscrobbler.com/2.0/?method=track.getinfo&api_key=b25b959554ed76058ac220b7b2e0a026&artist=cher&track=believe

那我该怎么办？

【问题讨论】：

标签： c# asp.net-mvc-3 xml-parsing xml-deserialization

【解决方案1】：

尝试将您的 fm 类重命名为 lfm。

public class lfm
{
    public Track track { get; set; }
}

然后你也可以去掉 xRoot 变量：

XmlSerializer xs = new XmlSerializer(typeof(lfm));
lfm rez = (lfm) xs.Deserialize(new MemoryStream(Encoding.UTF8.GetBytes(result)));

您也不需要[Serializable] 属性。这用于二进制序列化，并被XmlSerializer 类完全忽略。

【讨论】：

【解决方案2】：

fm 类的 lfm 属性必须将 track 作为其 XmlElement：

[Serializable()]
[XmlRoot(ElementName = "lfm", IsNullable = true)]
public class fm
{
    [XmlElement("track")]
    public Track lfm { get; set; }
}

【讨论】：