外部嵌套循环 Python 的累加器

Question

我正在从一本书中自学python并解决问题。在一个问题中，用户输入跨年的一年中每个月的降雨量。我需要找到每年的平均降雨量（sum（monthly rain）/numb_months，以及那个时期的平均降雨量，例如两年。在下面的代码中，我可以得到每年的平均值（我只用了 3 个月而不是 12 个月，以避免现在繁琐的输入），但我不知道我需要在哪里放置那个时期的总降雨量的蓄能器，然后平均它。感谢您的帮助。

number_of_months = 3
years_in_period = int(input("Please enter the number of years in the period. \n"))

for year in range(years_in_period):
    yearly_rain = 0
    print('Year', year+1) 
    print('−−−−−−−−−−−−−−−−−')
    for month in range(number_of_months):
        print('Month', month+1, end='')
        monthly_rain = float(input("Please enter rainfall for this month: \n"))
        yearly_rain += monthly_rain
        average_yearly_rainfall = yearly_rain / number_of_months
    print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
    print("Year total rain is", yearly_rain)
    print()

Answer 1

如果我明白你想要什么（计算期间降雨量的绝对平均值），这应该可以解决问题：

number_of_months = 3
years_in_period = int(input("Please enter the number of years in the period. \n"))

total_rain = 0

for year in range(years_in_period):
    yearly_rain = 0
    print('Year', year+1) 
    print('−−−−−−−−−−−−−−−−−')

    for month in range(number_of_months):
        print('Month', month+1, end='')
        monthly_rain = float(input("Please enter rainfall for this month: \n"))

        yearly_rain += monthly_rain

        total_rain += monthly_rain

        average_yearly_rainfall = yearly_rain / number_of_months

    print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
    print("Year total rain is", yearly_rain)
    print()


total_months = years_in_period * number_of_months
print("Absolute average of rain/month was", total_rain/total_months)
print("Absolute average of rain/year was", total_rain/years_in_period)