PowerShell 和 XAML 数据绑定

Question

我正在尝试获取按姓氏属性搜索的用户列表并将其列在 ListView 中。

这是 XAML 代码：

<Window
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
Title="Find users with SamAccountName"
Width="525"
Background="#FF262626"
ResizeMode="NoResize"
SizeToContent="Height">


<StackPanel Margin="5,5,5,5" Orientation="Vertical">


    <Grid
        Name="Grid"
        Width="400"
        Height="200"
        Background="#313130">
        <Label
            Name="Label"
            Content="Select employee"
            FontSize="12"
            Foreground="White" />
        <ListView
            Name="ListView"
            Margin="0,25,0,0"
            Background="Transparent"
            BorderBrush="Transparent"
            Foreground="White"
            IsHitTestVisible="False"
            SelectionMode="Single">
            <ListView.View>
                <GridView>
                    <GridViewColumn
                        Width="100"
                        DisplayMemberBinding="{Binding Path=Logon}"
                        Header="Logon" />
                    <GridViewColumn
                        Width="150"
                        DisplayMemberBinding="{Binding Path=FirstName}"
                        Header="First name" />
                    <GridViewColumn
                        Width="150"
                        DisplayMemberBinding="{Binding Path=LastName}"
                        Header="Last name" />
                </GridView>
            </ListView.View>
        </ListView>
    </Grid>

    <StackPanel HorizontalAlignment="Right">
        <Button Width="50" Content="SAVE" />
    </StackPanel>

</StackPanel>

它看起来像这样： XAML look

我相信如果没有数据绑定我就无法做到这一点，我看到了很多关于它们的帖子，但我无法完全理解。

现在在 powershell 中我有：

Add-Type -AssemblyName PresentationFramework

$employees = Get-ADUser -Filter {Surname -like "surname"}

$itemSource = @()

ForEach ($employee in ($employees | Sort-Object SamAccountName)) {

$itemSource += [PSCustomObject]@ {

    Logon = $employee.Name
    FirstName = $employee.GivenName
    LastName = $employee.Surname

}

$columnOrder = 'Logon', 'FirstName', 'LastName'

[XML]$Form = Get-Content "xmlPath"

$NR = (New-Object System.Xml.XmlNodeReader $Form)
$Win = [Windows.Markup.XamlReader]::Load($NR)

$Win.ShowDialog()

现在，ForEach 工作得非常好，并且完全返回了我需要的内容，但找不到任何方法将其放入 ViewList。

然后我需要将选定的用户保存到稍后在文本框中显示的变量中。

对不起，如果这是一个愚蠢/简单的问题，但我刚刚开始学习 PowerShell 来帮助我自动化我的工作。

Answer 1

在加载的表单中，你必须specify the ListView's ItemsSource

在 PowerShell 中，你可以这样做

Add-Type -AssemblyName PresentationFramework
$employees = Get-ADUser -Filter {Surname -like "surname"}

$itemSource = @()

ForEach ($employee in $($employees | Sort-Object SamAccountName)) {

    $itemSource += [PSCustomObject]@{

        Logon = $employee.Name
        FirstName = $employee.GivenName
        LastName = $employee.Surname

    }
}
[XML]$Form = (Get-Content "C:\temp\test.xaml")
$NR = (New-Object System.Xml.XmlNodeReader $Form)
$Win = [Windows.Markup.XamlReader]::Load($NR)
# this part
($win.FindName("ListView")).ItemsSource = $itemSource

$Win.ShowDialog()