【发布时间】：2016-08-10 13:47:10
【问题描述】：
我想从联系人电子邮件中检索联系人姓名，所以我所做的工作如下来自https://stackoverflow.com/a/18064869/5738881。
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
然后在onCreate()中，我编码为，
sName = readContacts(getApplicationContext(), sEmail);
etName.setText(sName);
但我得到的是空值。因此，仅根据联系人电子邮件地址获取联系人姓名的解决方案是什么？
EDIT-1：
我已经在清单中提到了权限，
<uses-permission android:name="android.permission.READ_CONTACTS"/>
EDIT-2：
根据 ROHIT SHARMA 的回答，我将代码更改如下。
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.getCount() > 0) {
cursor.moveToFirst();
} else {
return null;
}
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
但这对我也没有帮助。
EDIT-3：
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
String contactName = null;
if(cursor!=null && cursor.getCount()>0 )
{
cursor.moveToFirst();
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}else{
return null;
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
这对我也没有帮助。
EDIT-4：
我试过了
public String readContacts(Context context, String email) {
String name = null;
// define the columns I want the query to return
String[] projection = new String[]{
ContactsContract.PhoneLookup.DISPLAY_NAME,
ContactsContract.PhoneLookup._ID};
// encode the email and build the filter URI
Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
// query time
Cursor cursor = context.getContentResolver().query(contactUri, projection, null, null, null);
if (cursor != null) {
if (cursor.moveToFirst()) {
name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
Log.e("....email.....", "Started uploadcontactphoto: Contact Found @ " + email);
Log.e("....name....", "Started uploadcontactphoto: Contact name = " + name);
} else {
Log.e("....email exception....", "Contact Not Found @ " + email);
}
cursor.close();
}
return name;
}
来自https://stackoverflow.com/a/15007980/5738881，但也没有帮助。
有人有其他出路吗？
EDIT-5：
public String readContacts() {
ContentResolver cr = getContentResolver();
@SuppressLint("Recycle")
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
String id, name = null, email = null;
if (cur != null && cur.getCount() > 0) {
while (cur.moveToNext()) {
id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
System.out.println("name : " + name + ", ID : " + id);
// get the phone number
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
if (pCur != null) {
while (pCur.moveToNext()) {
String phone = pCur.getString(
pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
System.out.println("phone" + phone);
}
}
if (pCur != null) {
pCur.close();
}
// get email and type
Cursor emailCur = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
new String[]{id}, null);
if (emailCur != null) {
while (emailCur.moveToNext()) {
// This would allow you get several email addresses
// if the email addresses were stored in an array
email = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
String emailType = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
}
}
}
return name;
}
我从http://www.coderzheaven.com/2011/06/13/get-all-details-from-contacts-in-android/ 尝试了上面的代码实例，我得到了名字，但它与电子邮件 ID 所有者的名字不同。
那么，告诉我哪里出错了..
从上面的代码sn-p，我也试过了
if (email == sEmail) {
sName = name;
}
System.out.println("Email " + email + " Email Type : " + emailType);
}
}
if (emailCur != null) {
emailCur.close();
}
而不是
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
但也没有帮助。
【问题讨论】：
标签： android email android-contacts android-contentresolver contactscontract