【发布时间】:2020-01-18 10:57:35
【问题描述】:
我运行以下程序:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title> Slider </title>
<!-- jQuery CDN https://code.jquery.com/ -->
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript"src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
<script>
$(document).ready(function() {
console.debug("jQuery "+ (jQuery ? $().jquery : "NOT") +" loaded"); // jQuery version to console
$('#slider1').slider({value: "11"}); // initialize slider
$("#slider1").slider("option", "value", 2);
$("#slider1" ).slider("value", 3 );
var value = $( "#slider1" ).slider( "option", "value"); // show slider value
$('#sliderVal').text("Slider Value: "+value);
$('#slider1').on('input', function(event) { // show slider value when changed
var valSlider1 = $(this).attr('id') +" Value:" +$(this).val();
$('#sliderVal').text(valSlider1);
});
});
</script>
</head>
<body>
<p> Slider </p>
<input type="range" class="sl" id="slider1" min="0" max="100" value="99">
<p id="sliderVal">...</p //display value of slider
</body>
</html>
运行程序后,滑块的“拇指”仍然停留在 99
输出(id=sliderVal;倒数第二行)显示:滑块值:3
我试过了
$('#slider1').slider({value: "11"});
$("#slider1").slider("option", "value", 2);
$("#slider1" ).slider("value", 3 );
它们都改变了滑块的值,但滑块拇指从不移动。 当我用鼠标移动滑块的拇指时,会显示正确的值
【问题讨论】: