UIAutomation 单击按钮而不使窗口获得焦点并且 GetCurrentPattern() 返回不支持的模式

Question

我有一个窗口的句柄，我想做的是单击它的名为“加载设置”的按钮。我有 2 个问题。

• 我的第一个问题是当我在某个 InvokePattern 上调用 Invoke 时，它​​会使窗口成为焦点，这对我的应用程序来说是不可取的。

• 我的第二个问题是可见的，并记录在我的以下代码末尾的 cmets 中：

  AutomationElement aeBot = AutomationElement.FromHandle(mbotSettingList.ElementAt(i).getWindowHandle());
  AutomationElement aeButtonLoadSettings = aeBot.FindFirst(TreeScope.Children, new PropertyCondition(AutomationElement.NameProperty, "Load Settings"));
  InvokePattern ipClickLoadSettings = (InvokePattern)aeButtonLoadSettings.GetCurrentPattern(InvokePattern.Pattern);
  Thread invokeLoadSettingsThread = new Thread(ipClickLoadSettings.Invoke);
  InvokePattern ipClickOpen = null;
  AutomationElement aeOpenDialogEdit = null;
  AutomationElement aeButtonOpen = null;
  AutomationElementCollection aeDialogs = null;
  AutomationElement aeOpenDialog = null;
  ValuePattern vpOpenDialogEdit = null;
  
  //Using a thread to invoke the Load Settings button click because as a result of clicking Load Settings a dialog is opened and invoke doesnt return for nealy 10 seconds
  invokeLoadSettingsThread.Start();
  //We probably wont join() this thread because it goes on for far longer than we expect to be in this function
  
  //Get a collection of the Dialog windows that are direct children of the main window we have a handle to
  aeDialogs = aeBot.FindAll(TreeScope.Children, new PropertyCondition(AutomationElement.ClassNameProperty, "#32770"));
  
  while (aeDialogs.Count == 0)
  {
      //This while loop is to continue to check for the Open file dialog as it may take a little time to open
      aeDialogs = aeBot.FindAll(TreeScope.Children, new PropertyCondition(AutomationElement.ClassNameProperty, "#32770"));
      Thread.Sleep(250);
  }
  
  for (int j = 0; j < aeDialogs.Count; j++)
  {
      //There is usually only 1 child dialog window, but just make sure we have the correct one
      if (aeDialogs[j].Current.Name == "Open")
      {
          Debug.WriteLine("Found open dialog!");
          aeOpenDialog = aeDialogs[j];
          break;
      }
  }
  
  //Inside the Open window, the first Edit window is the one where the file name/path should be entered
  aeOpenDialogEdit = aeOpenDialog.FindFirst(TreeScope.Descendants, new PropertyCondition(AutomationElement.ClassNameProperty, "Edit"));
  
  //Set the value of the file name/path to the string variable "loadSettingsString"
  vpOpenDialogEdit = (ValuePattern)aeOpenDialogEdit.GetCurrentPattern(ValuePattern.Pattern); 
  vpOpenDialogEdit.SetValue(loadSettingsString);
  
  //******************************************PROBLEM BEGINING BELOW******************************************
  
  //Using multiple methods, we can successfully get a successful AutomationElement for the "Open" button in the Open file dialog
  aeButtonOpen = aeOpenDialog.FindFirst(TreeScope.Subtree, new PropertyCondition(AutomationElement.NameProperty, "Open"));
  
  //aeButtonOpen = aeOpenDialog.FindFirst(TreeScope.Subtree, new PropertyCondition(AutomationElement.NameProperty, "Cancel"));
  //Something to consider: If we assigned aeButtonOpen to the AutomationElement we find be looking for "Cancel" rather than "Open"
  
  Debug.WriteLine(aeButtonOpen.Current.Name + " button found!");
  //Prints "Open button found!"
  //If aeButtonOpen were assigned to "Cancel", this would print "Cancel button found!"
  
  ipClickOpen = (InvokePattern)aeButtonOpen.GetCurrentPattern(InvokePattern.Pattern);
  //GetCurrentPattern has returned null
  //If aeButtonOpen were assigned to "Cancel", this would NOT be null
  
  ipClickOpen.Invoke();
  //Invoke() on a null results in "Unsupported Pattern" exception
  //If aeButtonOpen were assigned to "Cancel", this would work and the Open file dialog would then be exited just as if cancel were clicked
  

Answer 1

使用UIAVerify 查看应用程序的 UIA 树。查看您的代码，我怀疑您没有检索您认为的元素。如果 'Open' 元素是一个按钮，它应该支持 Invoke 模式。

或者，您正在打开一个对话框，然后立即搜索该对话框的子元素。您可能会在此处遇到可靠性问题，其中仍在为该对话框创建 UIA 树。要检查这一点，请添加一秒钟的睡眠时间，看看是否能解决您的问题。如果是这种情况，请查看 UIA 结构更改事件。这些事件将让您根据 UIA 树中的更改同步您的 UIA 测试代码。