【问题标题】:moving current file open in dialog to directory将对话框中打开的当前文件移动到目录
【发布时间】:2014-01-27 22:14:09
【问题描述】:

在这里我打开一个文件,但我不会打开它然后移动到另一个目录中的文件夹,如果程序是这里的代码我到目前为止得到的代码

 Public Class Form1

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

    OpenFileDialog1.Title = "Please Select a File"

    OpenFileDialog1.InitialDirectory = "C:temp"

    OpenFileDialog1.ShowDialog()

End Sub

Private Sub OpenFileDialog1_FileOk(ByVal sender As System.Object, ByVal e As System.ComponentModel.CancelEventArgs) Handles OpenFileDialog1.FileOk

    Dim strm As System.IO.Stream

    strm = OpenFileDialog1.OpenFile()

    TextBox1.Text = OpenFileDialog1.FileName.ToString()

    If Not (strm Is Nothing) Then

        'insert code to read the file data

        strm.Close()

        MessageBox.Show("File Opened")

    End If

End Sub

结束类

【问题讨论】:

  • 你看过System.IO.File类吗?

标签: vb.net openfiledialog


【解决方案1】:

首先...这甚至不是目录。

"C:temp"

如果您希望 OpenFileDialog1 控件的初始目录与您的应用程序所在的目录相同...试试这个...

OpenFileDialog1.InitialDirectory = Application.StartupPath

【讨论】:

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