抛出错误“输入字符串的格式不正确”？ C# Windows 窗体

Question

我正在尝试读取 .csv 文件，但它抛出错误 input string was not in correct format。这是我的.csvexcel文件截图LINK

这是上课

 class DowStock
{
    public string coName { get; set; }
    public double coPrice { get; set; }
    public double coChange { get; set; }
    public decimal coChangePct { get; set; } 
    public long coVolume { get; set; } 
    public decimal coYTDchange { get; set; } 
}

这是表单代码

 static DowStock SplitRow(string Row) { 
  DowStock rowResult = new DowStock(); 
  string[] splitRow = Row.Split(",".ToCharArray()); 
  rowResult.coName = splitRow[0]; 
  rowResult.coPrice = double.Parse(splitRow[1]); 
  rowResult.coChange = double.Parse(splitRow[2]); 
  rowResult.coChangePct = decimal.Parse(splitRow[3]); 
  rowResult.coVolume = long.Parse(splitRow[4]);
  rowResult.coYTDchange = decimal.Parse(splitRow[5]);
  return rowResult; 
}

Answer 1

如您所见，某些列的 #### 不能转换为 Double 值并导致异常，处理这种情况的最佳选项是 TryParse，它将为您提供最小值或默认值如果转换失败，则为该特定类型。所以我建议你使用double.TryParse、Int64.TryParse和decimal.TryParse进行转换。

例如：让我们考虑rowResult.coPrice = double.Parse(splitRow[1]); 来获取这个值，我们可以像下面这样使用：

double coPrice = 0.0;
double.TryParse(splitRow[1], out coPrice);
rowResult.coPrice = coPrice;
// The value will be 0.0 if the input is not convertible or
// else it will be populated with the required value

这样就可以逃离FormatException