尝试从 /lib (ROR) 中的类调用 _path 或 _url

Question

我正在尝试为登录时触发的用户构建一个“路由器”。我正在尝试按角色重定向用户。

我有以下：

require "#{Rails.root}/lib/client/user_router"

class ApplicationController < ActionController::Base
 # Prevent CSRF attacks by raising an exception.
 # For APIs, you may want to use :null_session instead.
 protect_from_forgery with: :exception
 add_flash_types :info

 def after_sign_in_path_for(user)
  UserRouter.new(user)
end

结束

在 /lib/user_router.rb

中

 class UserRouter
 include Rails.application.routes.url_helpers

  def initialize(user)
    @user = user
    route_user_by_role
  end

  def route_user_by_role
    if @user.is_pt_master?
      pt_master_root_url
    elsif @user.is_traveler?
      traveler_root_url
    elsif @user.client_user_role?
      route_client_by_role
    else
      root_url
    end
  end

  def route_client_by_role
    if @user.is_super_admin?
      for_super_admin
    else
      for_other_admin
    end
  end

  def for_super_admin
    if @user.client_account.blank?
      edit_client_account_url
     else
      client_root_url
    end
  end

  def for_other_admin
    if @user.is_first_sign_in? || @user.client_user_info.blank?
      edit_client_user_info_url(@user)
    else
      client_root_url
    end
  end
end

我正在使用 _url 因为如果我使用 _path 我会收到一个 .to_model 错误，但是使用 _url 我会得到 缺少要链接的主机！请提供 :host 参数，设置 default_url_options[:host]，或设置 :only_path 为 true

我已经在 config/environments 中将默认主机设置为 localhost:3000。任何有关如何执行此操作的帮助将不胜感激。

Answer 1

将default_url_options 添加到UserRouter：

class UserRouter
  include Rails.application.routes.url_helpers

  def self.default_url_options
    {host: 'localhost:3000'}
  end

  def initialize(user)
    @user = user
    route_user_by_role
  end

  def route_user_by_role
    if @user.is_pt_master?
      pt_master_root_url
    elsif @user.is_traveler?
      traveler_root_url
    elsif @user.client_user_role?
      route_client_by_role <= breaks here with undefined method error
    else
      root_url
    end
  end

  def route_client_by_role
    if @user.is_super_admin?
      for_super_admin
    else
      for_other_admin
    end
  end

  def for_super_admin
    if @user.client_account.blank?
      edit_client_account_url
    else
      client_root_url
    end
  end

  def for_other_admin
    if @user.is_first_sign_in? || @user.client_user_info.blank?
      edit_client_user_info_url(@user)
    else
      client_root_url
    end
  end
end

Answer 2

所以我不能像我想要的那样将它作为 /lib/ 中的类来做，但是将它作为控制器问题拉到一个模块中允许我将逻辑与 ApplicationController分开> 就像我想的那样，它并不理想，但总比把它全部塞进 App Cntrl 好。

class ApplicationController < ActionController::Base
  include UserRouter
  ...    

  def after_sign_in_path_for(user)
    initialize_user_router(user)
  end

  ...
end


module UserRouter
  def initialize_user_router(user)
    @user = user
    direct_user_by_role
  end

  def direct_user_by_role
    if @user.is_pt_master?
      pt_master_root_path
    elsif @user.is_traveler?
      direct_traveler
    elsif @user.client_user_role?
      direct_client_by_role
    else
      root_path
    end
  end
  def direct_traveler
    ...
    traveler_root_path
  end

  def direct_client_by_role
    if @user.is_super_admin?
      direct_super_admins
    else
      direct_other_admins
    end
  end

  def direct_super_admins
    if @user.client_account.blank?
      edit_client_account_path
    else
      client_root_path
    end
  end

  def direct_other_admins
    if @user.first_sign_in? || @user.client_user_info.blank?
      edit_client_user_info_path(@user)
    else
      client_root_path
    end
  end
end