在新的 Unity 输入系统中如何映射到 KeyCode.JoystickButton0？

Question

我正在为 Android TV 和 Fire TV 开发一个 Unity 项目，该项目利用 v2019.3 中发布的新输入系统。

Fire TV's button mappings在旧系统中如下：

Back                    KeyCode.Escape
Select (D-Pad Center)   KeyCode.JoystickButton0
Left (D-Pad)            KeyCode.LeftArrow
Right (D-Pad)           KeyCode.RightArrow
Up (D-Pad)              KeyCode.UpArrow
Down (D-Pad)            KeyCode.DownArrow

我已经成功地在新系统中使用以下绑定路径映射了除 Select/D-Pad Center 之外的所有内容：

Escape [Keyboard]
Right Arrow [Keyboard]
Left Arrow [Keyboard]
Up Arrow [Keyboard]
Down Arrow [Keyboard]

如果我映射到Any Key [Keyboard] 并实现以下代码作为回调，它将显示为key: JoystickButton0，这与亚马逊的文档相匹配，但在新系统中的键盘绑定路径下不作为选项存在：

public void DebugKey(InputAction.CallbackContext context)
{
    foreach(KeyCode vKey in System.Enum.GetValues(typeof(KeyCode))){
         if(Input.GetKey(vKey)){
             Debug.Log ("key: " + vKey);
         }
    }
}

我尝试过Gamepad、Android Gamepad、Joystick和Android Joystick下的各种按钮，但均未成功。另一个奇怪的事情是，中心/方向键在没有任何绑定的 UI 按钮上工作正常。

使用新输入系统映射到旧版 KeyCode.JoystickButtonX 命名约定的正确方法是什么？

谢谢！

Answer 1

要使用 Unity 将 Amazon Fire Tv 控制器与新输入系统完全映射，您需要一个自定义设备。

使用此脚本，您可以使所有按钮正常工作。 也可以提高音量、降低音量和静音。但我认为覆盖此按钮不是一个好主意。

using System.Linq;
using UnityEngine;
using UnityEngine.InputSystem;
using UnityEngine.InputSystem.Controls;
using UnityEngine.InputSystem.Layouts;
using UnityEngine.InputSystem.LowLevel;
using UnityEngine.InputSystem.Utilities;
using UnityEngine.Scripting;
 
#if UNITY_EDITOR
using UnityEditor;
#endif
 
[Preserve]
public struct AftvRemoteDeviceState : IInputStateTypeInfo
{
    public FourCC format => new FourCC('A', 'G', 'C');
 
    //Mapped Here
    [InputControl(name = "dPadUpButton", layout = "Button", bit = 19, displayName = "Dpad Up")]
    [InputControl(name = "dPadRightButton", layout = "Button", bit = 22, displayName = "Dpad Right")]
    [InputControl(name = "dPadDownButton", layout = "Button", bit = 20, displayName = "Dpad Down")]
    [InputControl(name = "dPadLeftButton", layout = "Button", bit = 21, displayName = "Dpad Left")]
    //[InputControl(name = "backButton", layout = "Button", bit = 4, displayName = "Back Button")]
    [InputControl(name = "menuButton", layout = "Button", bit = 82, displayName = "Menu Button")]
    //Non Maped
    [InputControl(name = "selectButton", layout = "Button", bit = 23, displayName = "Select Button")]
    [InputControl(name = "rewindButton", layout = "Button", bit = 89, displayName = "Rewind Button")]
    [InputControl(name = "playPauseButton", layout = "Button", bit = 85, displayName = "Play Pause Button")]
    [InputControl(name = "fastForwardButton", layout = "Button", bit = 90, displayName = "Fast Forward Button")]
    public uint buttons;
}
 
#if UNITY_EDITOR
[InitializeOnLoad] // Call static class constructor in editor.
#endif
[Preserve]
[InputControlLayout(displayName = "Aftv Remote", stateType = typeof(AftvRemoteDeviceState))]
public class AftvRemoteDevice : InputDevice
{
#if UNITY_EDITOR
    static AftvRemoteDevice()
    {
        Initialize();
    }
#endif
 
    [RuntimeInitializeOnLoadMethod]
    private static void Initialize()
    {
        InputSystem.RegisterLayout<AftvRemoteDevice>
            (
                matches: new InputDeviceMatcher()
                .WithInterface("Android")
                .WithDeviceClass("AndroidGameController")
                .WithProduct("Amazon Fire TV Remote")
            );
    }
 
    public ButtonControl dPadUpButton { get; private set; }
    public ButtonControl dPadRightButton { get; private set; }
    public ButtonControl dPadDownButton { get; private set; }
    public ButtonControl dPadLeftButton { get; private set; }
    public ButtonControl selectButton { get; private set; }
    public ButtonControl rewindButton { get; private set; }
    public ButtonControl playPauseButton { get; private set; }
    public ButtonControl fastForwardButton { get; private set; }
    //public ButtonControl backButton { get; private set; }
    public ButtonControl menuButton { get; private set; }
    public bool SelectButtonDown { get; set; }
    public bool RewindButtonDown { get; set; }
    public bool PlayPauseButtonDown { get; set; }
    public bool FastForwardButtonDown { get; set; }
 
    protected override void FinishSetup()
    {
        base.FinishSetup();
        dPadUpButton = GetChildControl<ButtonControl>("dPadUpButton");
        dPadRightButton = GetChildControl<ButtonControl>("dPadRightButton");
        dPadDownButton = GetChildControl<ButtonControl>("dPadDownButton");
        dPadLeftButton = GetChildControl<ButtonControl>("dPadLeftButton");
 
        rewindButton = GetChildControl<ButtonControl>("rewindButton");
        playPauseButton = GetChildControl<ButtonControl>("playPauseButton");
        fastForwardButton = GetChildControl<ButtonControl>("fastForwardButton");
 
        //backButton = GetChildControl<ButtonControl>("backButton");
        menuButton = GetChildControl<ButtonControl>("menuButton");
        selectButton = GetChildControl<ButtonControl>("selectButton");    
    }
 
    public static AftvRemoteDevice current { get; private set; }
 
    public override void MakeCurrent()
    {
        base.MakeCurrent();
        current = this;
    }
 
    protected override void OnRemoved()
    {
        base.OnRemoved();
        if (current == this)
            current = null;
    }
 
    #region Editor
#if UNITY_EDITOR
    [MenuItem("Tools/AftvRemote/Create Device")]
    private static void CreateDevice()
    {
        InputSystem.AddDevice<AftvRemoteDevice>();
    }
    [MenuItem("Tools/AftvRemote/Remove Device")]
    private static void RemoveDevice()
    {
        var customDevice = InputSystem.devices.FirstOrDefault(x => x is AftvRemoteDevice);
        if (customDevice != null)
            InputSystem.RemoveDevice(customDevice);
    }
#endif
    #endregion
}

位值是相同的来自 Android API 的常量值。 您可以查看列表Here 您只需在项目设置中包含此脚本即可设置您的输入操作和输入操作映射。

由于某些原因，播放器输入组件存在问题。 但是对于 UI 导航，这很好用，它也适用于 Input Debugger。

Answer 2

在新系统中，设备被读取为HID，KeyCode没有用，所以如果你想读取摇杆按钮的状态，你可以这样做：

using UnityEngine.InputSystem;


public Joystick joy;

void Start()
{
     joy = Joystick.current;
}

void FixedUpdate()
{
    var button2 = joy.allControls[2].IsPressed();
    if (button2)
    {
        Debug.Log("Button2 of current joystick is pushed");
    }
}

如果你想映射 button0（在旧的输入系统中），它现在是 button1 或触发器

var button1 = joy.allControls[1].IsPressed();

或

var button1 = joy.trigger.IsPressed();

---

你可以测试更多棒的按钮..

void Start()
{
    var ListOfJoys = Joystick.all;
     joy = Joystick.current;//here current joy is ListOfJoys[1]
     otherjoy = ListOfJoys[0];
}


    var Buttons = joy.allControls;


    if ((Buttons[2] as ButtonControl).wasPressedThisFrame)
    {
        Debug.Log("b2 pressed during this frame");
    }
    if ((Buttons[2] as ButtonControl).wasReleasedThisFrame)
    {
        Debug.Log("b2 released during this frame");
    }
    if (joy.trigger.wasPressedThisFrame)
    {
        Debug.Log("trig or button1 pressed during this frame");
    }
    if (joy.trigger.wasReleasedThisFrame)
    {
        Debug.Log("trig or button1 released during this fram");
    }
    if (otherjoy.trigger.wasPressedThisFrame)
    {
        Debug.Log("otherjoy trigger");
    }

---

另一种方法是使用新系统的映射，我已经将动作press OnlyTest1映射到了stick的button3

简化代码，您可以混合使用事件和直接测试：

//Newinputsystem is a name of class generated 
private Newinputsystem playerAction;

void Awake()
{
    playerAction = new Newinputsystem();
    playerAction.Player.Test1.performed += ctx => FireTest();
}

void FixedUpdate()
{
    if (playerAction.Player.Test1.triggered)
    {
        Debug.Log("fire!!!");
    }
}

public void FireTest()
{
    Debug.Log("i am in firetest");
}

private void OnEnable()
{
    playerAction.Enable();
}
private void OnDisable()
{
    playerAction.Disable();
}

这样您就可以添加新的动作 test2，该动作将由动作 release only for button3 触发...

要显示 HID 设备，请转到菜单窗口/分析/输入调试器

您必须查看您的设备（这里我的是 hotas）

然后单击它并在选项卡项 HID 描述符中

所以我想你已经在项目设置中选择了你的设备：