如何在 Laravel 中压缩图像而不调整大小？答案

【问题标题】：How can I compress image in Laravel not resize?如何在 Laravel 中压缩图像而不调整大小？
【发布时间】：2019-11-24 22:51:52
【问题描述】：

我想在 laravel 上传中保存压缩图像。我找到了一个名为“intervention/image”的包。但它具有调整大小功能而不是压缩。

【问题讨论】：

这能回答你的问题吗？ Laravel image intervention compression
你可以试试 TinyPNG API

标签： laravel image-compression

【解决方案1】：

你可以这样做：

  public function compress($source, $destination, $quality = 75) {
    $info = getimagesize($source);
    if ($info['mime'] == 'image/jpeg') {
      $image = imagecreatefromjpeg($source);
    } elseif ($info['mime'] == 'image/gif') {
      $image = imagecreatefromgif($source);
    } elseif ($info['mime'] == 'image/png') {
      $image = imagecreatefrompng($source);
    }
    imagejpeg($image, $destination, $quality);
    return $destination;
  }

目的地可以和来源相同

【讨论】：

【解决方案2】：

      <form action="{{route('resizeImagePost')}}" method="POST" enctype="multipart/form-data">
      @csrf
      <div class="row">
            <div class="col-md-12">
                <br/>
                <input type="file" name="image" placeholder="image" class ="image">
            </div>
            <div class="col-md-12">
                <br/>
                <button type="submit" class="btn btn-success">Upload Image</button>
            </div>
        </div>
      </form>






   public function resizeImagePost(Request $request)
    {
        $this->validate($request, [
            'image' => 'required|image|mimes:jpeg,png,jpg,gif,svg|max:2048',
        ]);
        $image = $request->file('image');
        $upload_imagename = time().'.'.$image->getClientOriginalExtension();
        $upload_url = public_path('/images').'/'.$upload_imagename;
        $filename = $this->compress_image($_FILES["image"]["tmp_name"], $upload_url, 40);
        return back()
            ->with('success','Image Upload successful');
    }

   public  function compress_image($source_url, $destination_url, $quality) {
        $info = getimagesize($source_url);
            if ($info['mime'] == 'image/jpeg')
                    $image = imagecreatefromjpeg($source_url);
            elseif ($info['mime'] == 'image/gif')
                    $image = imagecreatefromgif($source_url);
            elseif ($info['mime'] == 'image/png')
                    $image = imagecreatefrompng($source_url);
            imagejpeg($image, $destination_url, $quality);
        return $destination_url;
    }

【讨论】：