C# List<T> 继承

Question

假设我有一个名为 Field 的类

public class Field
{
    public string name {get;set;}
    public string type {get;set;}

}

对于我的程序，我需要构建一个列表，但列表中的某些字段是通用的，并且会在程序的少数部分中重复，我想将那些将被复制的字段分离到一个基类中，以便那些子类可以从基类继承而无需重复某些字段。 概念大致如下：

base classA {
    List<Field> list = new List<Field>();
    list.add(new Field(){name = "fieldNameA", type = "typeA"});
    list.add(new Field(){name = "fieldNameB", type = "typeB"});
    list.add(new Field(){name = "fieldNameC", type = "typeC"});
}

base classB {
    List<Field> list = new List<Field>();
    list.add(new Field(){name = "fieldNameX", type = "typeX"});
    list.add(new Field(){name = "fieldNameY", type = "typeY"});
    list.add(new Field(){name = "fieldNameZ", type = "typeZ"});
}


sub class {

   private void methodA() {
      //Inherits list initialized at 
      //     **base classA** above, 
      //and continues to initialize some other Fields

     list.add(new Field(){name = "fieldNameD", type = "typeD"});
     list.add(new Field(){name = "fieldNameE", type = "typeE"});

      //so at here finally i would have list which consists of fieldNameA to fieldName E
    }


    private void methodB() {
      //Inherits list initialized at 
      //      **base classB** above, 
      //and continues to initialize some other Fields

     list.add(new Field(){name = "fieldNameD", type = "typeD"});
     list.add(new Field(){name = "fieldNameE", type = "typeE"});

      //so at here finally i would have list which consists of fieldNameX, Y,Z,D,E
    }
}

我应该怎么做才能实现这一目标？

Answer 1

我不确定你的意思是不是这样的构图：

class BaseClass {
    protected List<Field> list = new List<Field>();
    public BaseClass()
    {           
       list.add(new Field(){name = "fieldNameA", type = "typeA"});
       list.add(new Field(){name = "fieldNameB", type = "typeB"});
       list.add(new Field(){name = "fieldNameC", type = "typeC"});
    }
}

class SubClass : BaseClass {
    public SubClass() : base()  
    {           
       list.add(new Field(){name = "fieldNameD", type = "typeD"});
       list.add(new Field(){name = "fieldNameE", type = "typeE"});
    }
}