XPath 根据子节点选择父节点答案

【问题标题】：XPath Select parent node based on child nodeXPath 根据子节点选择父节点
【发布时间】：2019-07-10 07:04:30
【问题描述】：

我需要提取其后代所在的href：i/[@class="icon-right-open rotate180"]

我尝试了以下方法，但对我不起作用

//a[@class="arrowDot "]/@href /descendant::i[@class="icon-right-open rotate180"]

这是 HTML 代码：

<div class="paginationDots sMargTop centered">
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:2:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="arrowDot ">
        <i class="icon-left-open rotate180"/>
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        1
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:2:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        2
    </a>
    <a class="Dots currentDot">
                        3
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:4:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        4
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:5:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        5
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:6:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        6
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:7:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="Dots ">
                        7
    </a>
    <a href="https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:4:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale" class="arrowDot ">
        <i class="icon-right-open rotate180"/>
    </a>
</div>

预期结果是以下网址： https://www.mubawab.tn/fr/cc/immobilier-a-vendre-all:p:4:sc:apartments-for-sale,commercial-property-for-sale,farms-for-sale,houses-for-sale,land-for-sale,villas-and-luxury-homes-for-sale 但实际输出为空

【问题讨论】：

什么语言？这是通过在线工具完成的吗？

标签： xpath web-scraping xpath-2.0 descendant

【解决方案1】：

你几乎猜对了。这是您需要的。

//a[@class="arrowDot "][descendant::i[@class="icon-right-open rotate180"]]/@href

【讨论】：