【发布时间】:2014-11-11 11:57:07
【问题描述】:
好的。所以基本上。这是我的代码。
login.php
require_once("./libs/db_cxn.php");
$cxn = new newConnection();
$stmt = "SELECT users.username FROM users WHERE username=$username AND password=MD5($password)";
$qry = \mysqli_prepare($cxn, $stmt);
$res = mysqli_execute($qry);
db_cxn.php
class newConnection{
function __construct(){
$conf = array(
"host" => "localhost",
"username" => "root",
"password" => "root",
"dbname" => "db_BookWorm",
"port" => ini_get("mysqli.default_port"),
"socket" => ini_get("mysqli.default_socket"),
"prefix" => "bWorm_"
);
$cxn = new mysqli($conf["host"], $conf["username"], $conf["password"], $conf["dbname"]);
if ($cxn->connect_errno){
\printf("Connection failed: %s\n", $cxn->connect_error);
exit();
}
}
function _destruct(){
mysqli_close($this);
}
}
我有错误报告,每当我尝试运行该代码时都会给出以下错误消息
Warning: mysqli_prepare() expects parameter 1 to be mysqli, object given in \\MORIARTY\HOME\15\5CBA2901\Desktop\comp_proj\project\www\login.php on line 34
关于如何解决这个问题的任何线索?由于我打开连接的频率,我创建了这个连接类,并认为它可以节省我的时间和悲伤。任何帮助将不胜感激!
【问题讨论】:
-
传递给
mysqli_prepare的$cxn是newConnection类型的对象实例。但是mysqli_prepare需要mysqli类型的对象实例。您所做的根本不是对象的工作方式。