PHP将值从php文件传递给其他类答案

【问题标题】：PHP pass values from php file to other classPHP将值从php文件传递给其他类
【发布时间】：2018-01-12 10:34:32
【问题描述】：

我将 config.php 文件用于类似的东西，我试图将我的 mysql 凭据放在那里，然后在不同的文件中使用它们，但它没有传递值，

有没有什么1可以帮助我找到解决方案。

代码配置.php：

/* Database credentials*/
$dbHost = 'localhost';
$dbName = 'xx';
$dbUsername = 'xx';
$dbWachtwoord = 'xx';

代码dbconnect.php：

<?php include 'config.php';
class Database
{
    private $host;
    private $db_name;
    private $username;
    private $password;
    public $conn;

    public function dbConnection()
    {
        $this->host = $dbHost;
        $this->db_name = $dbName;
        $this->username = $dbUsername;
        $this->password = $dbWachtwoord;
        $this->conn = null;
        try
        {
            $this->conn = new PDO("mysql:host=" . $this->host . ";dbname=" . $this->db_name, $this->username, $this->password);
            $this->conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        }
        catch(PDOException $exception)
        {
            echo "Connection error: " . $exception->getMessage();
        }

        return $this->conn;
    }
}

Class.user 数据库连接：

<?php
require_once('config.php');
require_once('dbconnect.php');

class USER
{   

    private $conn;

    public function __construct()
    {
        $database = new Database();
        $db = $database->dbConnection();
        $this->conn = $db;
    }

    public function runQuery($sql)
    {
        $stmt = $this->conn->prepare($sql);
        return $stmt;
    }

提前致谢 =)

【问题讨论】：

变量范围：php.net/manual/en/language.variables.scope.php
向我们展示如何调用 dbConnection() 方法。然后有人可以帮助你。
$this->host = $GLOBALS['dbHost'];

标签： php mysql class private

【解决方案1】：

与其将其视为传递变量，不如将其视为传递配置。您的数据库类必须了解这些配置选项才能使用它。换句话说：一旦您创建了类 Database 的实例，就应该对其进行配置并准备好使用，就像任何服务一样。我强烈建议你遵守injecting the configuration as a dependency的规则。

【讨论】：

【解决方案2】：

在你的类中包含'config.php

 public function dbConnection()
    {
        include 'config.php';
        $this->host = $dbHost;
        $this->db_name = $dbName;
        $this->username = $dbUsername;
        $this->password = $dbWachtwoord;
        $this->conn = null;
        try
        {

【讨论】：

【解决方案3】：

你可以试试下面的代码：

config.php

<?php 
return [
    'dbHost' => 'localhost',
    'dbName' => 'xx',
    'dbUsername' => 'xx',
    'dbWachtwoord' => 'xx',
];

用户类

class USER
{   

    private $conn;
    private $config;

    public function __construct()
    {
        $this->config = include "config.php";
        $database = new Database(this->config['dbHost'], $this->config['dbUsername'], $this->config['dbWachtwoord'], $this->config['dbName']);
        //...
    }
    //...
}

dbconnect.php

public function dbConnection($dbHost, $dbName, $dbWachtwoord, $dbName)
{
    //....
}

【讨论】：