将多个字符串传递给函数并附加到列表

Question

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, trick ):
     self.tricks.extend(trick)

我不断收到 add_tricks 只接受 1 个位置参数但给出了 3 个的错误消息。我尝试将 **kwargs 传递给该函数，但这也不起作用。如何将多个字符串传递给函数？

Answer 1

For (*args) parameters as ("Hello","Byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, *trick):
     self.tricks.extend(trick)

For (**kwargs) parameters as (a="Hello",b="Byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, **trick):
     self.tricks.extend(trick)

Or if you want to give string in both types like (a="Hello","byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, *trick1,**trick2):
     self.tricks.extend(trick)
     self.tricks.extend(trick2)