使用 jQuery 的非常简单和轻量级的解决方案:
背后的代码:
public partial class GridViewCellColourChange : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if(!Page.IsPostBack)
{
gvItems.DataSource = this.GetData();
gvItems.DataBind();
}
}
private IEnumerable<Item> GetData()
{
var item1 = new Item { item = "itm1", prop1 = "23", prop2 = "asd", prop3 = "23d", values = "0-0-0-0-0" };
var item2 = new Item { item = "itm2", prop1 = "43", prop2 = "asd", prop3 = "23d", values = "0-0-0-0-0" };
var item3 = new Item { item = "itm3", prop1 = "53", prop2 = "asd", prop3 = "23d", values = "0-0-0-0-0" };
return new List<Item> { item1, item2, item3 };
}
}
public class Item
{
public string item { get; set; }
public string prop1 { get; set; }
public string prop2 { get; set; }
public string prop3 { get; set; }
public string values { get; set; }
}
.ASPX:
<head runat="server">
<title></title>
<script src="https://code.jquery.com/jquery-1.12.2.min.js"></script>
<script>
$(function () {
$("#gvItems > tbody > tr").each(function (i, row) {
var children = $(row).children();
for(var i=0; i < children.length;i++)
{
var child = children[i];
if(child.localName == "td")
{
var text = $(child).text();
if(text == "23")
{
$(child).css("background-color", "red");
}
else if(text == "43")
{
$(child).css("background-color", "green");
}
}
}
});
});
</script>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:GridView ID="gvItems" runat="server"></asp:GridView>
</div>
</form>
</body>
输出: