Android在打字时显示Listview

Question

我有带有自定义适配器的Listview。我将Searchview 放在活动栏中以过滤Listview 中的项目。 Mycustom Listview 和 Searchview 工作正常。 我希望我的Listview 以空开头，但只根据输入Searchview 显示项目

我的代码示例

主活动

 @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    lv = (ListView) findViewById(R.id.listView);
    btnsrc = (Button) findViewById(R.id.btnSearch);

    SeaFoodData food = new SeaFoodData(this);
    ArrayList<SeaFood> sList = new ArrayList<SeaFood>();

    try {
        sList = food.GetSeaFood();
    } catch (JSONException e) {
        e.printStackTrace();
    }

     sfAdapter = new SeaFoodAdapter(MainActivity.this, sList);
     lv.setAdapter(sfAdapter); 

    lv.setTextFilterEnabled(true);
    filter = sfAdapter.getFilter();


}

@Override
public boolean onQueryTextChange(String newText)
{

    filter.filter(newText);

    return true;
}

@Override
public boolean onQueryTextSubmit(String query) {
    return false;
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    MenuInflater inflater = getMenuInflater();
    // Inflate menu to add items to action bar if it is present.
    inflater.inflate(R.menu.menu_main, menu);
    // Associate searchable configuration with the SearchView
    SearchManager searchManager =
            (SearchManager) getSystemService(Context.SEARCH_SERVICE);
    SearchView searchView =
            (SearchView) menu.findItem(R.id.action_search).getActionView();
    searchView.setSearchableInfo(
            searchManager.getSearchableInfo(getComponentName()));

    sv = (SearchView) menu.findItem(R.id.action_search).getActionView();
    searchView.setQueryHint("Ara...");

    setupSearchView();

    return true;
}


private void setupSearchView()
{
    sv.setOnQueryTextListener(this);
}

我的适配器

    public SeaFoodAdapter(Context ctx, ArrayList<SeaFood> foodList) {
    super();
    this.context = ctx;
    this.seaFoodArrayList = foodList;

}




public class SeaFoodHolder
{
    TextView food;
    TextView description;
    ImageView rsm;

}

public Filter getFilter() {
    return new Filter() {

        @Override
        protected FilterResults performFiltering(CharSequence constraint) {
            final FilterResults oReturn = new FilterResults();
            final ArrayList<SeaFood> results = new ArrayList<SeaFood>();
            if (orig == null)
                orig = seaFoodArrayList;
            if (constraint != null) {
                if (orig != null && orig.size() > 0) {
                    for (final SeaFood g : orig) {
                        if (g.getName().toLowerCase()
                                .contains(constraint.toString()))
                            results.add(g);
                    }


                }
                oReturn.values = results;
            }
            return oReturn;
        }

        @SuppressWarnings("unchecked")
        @Override
        protected void publishResults(CharSequence constraint,
                                      FilterResults results) {
            seaFoodArrayList = (ArrayList<SeaFood>) results.values;
            notifyDataSetChanged();
        }
    };
}

public void notifyDataSetChanged() {
    super.notifyDataSetChanged();
}


@Override
public int getCount() {
    return seaFoodArrayList.size();
}

@Override
public SeaFood getItem(int position) {
    return seaFoodArrayList.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    SeaFoodHolder holder;
    if(convertView==null)
    {
        convertView=LayoutInflater.from(context).inflate(R.layout.row, parent, false);
        holder=new SeaFoodHolder();
        holder.food=(TextView) convertView.findViewById(R.id.tvFood);
        holder.description=(TextView) convertView.findViewById(R.id.tvDescription);
        holder.rsm=(ImageView) convertView.findViewById(R.id.warnimage);
        convertView.setTag(holder);
    }
    else
    {
        holder=(SeaFoodHolder) convertView.getTag();
    }

    holder.food.setText(seaFoodArrayList.get(position).getName());
    holder.description.setText(String.valueOf(seaFoodArrayList.get(position).getDescription()));


    if (seaFoodArrayList.get(position).getimgPath().equals("0") ) {
        holder.rsm.setImageResource(R.drawable.error);
    } else {
        holder.rsm.setImageResource(R.drawable.check);
    }

    if (position % 2 == 0) {
        convertView.setBackgroundColor(Color.parseColor("#E3F2FD"));
    } else {
        convertView.setBackgroundColor(Color.parseColor("#90CAF9"));
    }

    View vi = convertView;
    vi.setOnCreateContextMenuListener(this);

    return convertView;

}

public void onCreateContextMenu(ContextMenu contextMenu, View view, ContextMenu.ContextMenuInfo contextMenuInfo) {
     // empty implementation
   }

已解决

我解决了这个问题。

首先，

在设置适配器后，我在 On Create 函数中隐藏了我的 Listview。

    sfAdapter = new SeaFoodAdapter(MainActivity.this, sList);
    lv.setAdapter(sfAdapter);

    lv.setTextFilterEnabled(true);
    filter = sfAdapter.getFilter();
    lv.setVisibility(View.GONE);

那么，

在onQueryTextChange函数中根据搜索查询显示ListView

@Override
public boolean onQueryTextChange(String newText)
{

    if(newText == null || newText.equals(""))
    {
        lv.setVisibility(View.GONE);
    }else{
        lv.setVisibility(View.VISIBLE);
    }

    filter.filter(newText);

    return true;
}

希望这对某人有所帮助。感谢您的帮助。

Answer 1

如果我理解你，只是想在搜索字段中没有任何内容时显示空列表视图？

public View getView(int position, View convertView, ViewGroup parent) {
if(searchFieldTextView.getText() == null || searchFieldTextView.getText().equals(""))
{
    //Return empty view
}else{
    //Return your listview content
}

这对你有意义吗？

希望这会有所帮助。

编辑：

要访问它，只需将其声明为静态

在 MainActivity 中

static SearchView searchField;

在你的 onCreateOptionsMenu 中添加

searchField = searchView;

或

searchfield = (SearchView) menu.findItem(R.id.action_search).getActionView();

然后访问它只需调用

MainActivity.searchField