检查时间并根据该时间运行程序的功能。

Question

我正在编写估算时间的函数。即根据时间运行特定事件...假设我有一个时间数组

$times = array(
    '00:00' => 'Programme 1',
    '00:30' => 'Programme 2',
    '01:00' => 'Programme 3',
    '01:30' => 'Programme 4',
    '02:00' => 'Programme 5',
    '02:30' => 'Programme 6',
    '03:00' => 'Programme 7',
    '03:30' => 'Programme 8',
    '04:00' => 'Programme 9',
    '04:30' => 'Programme 10',
    '05:00' => 'Programme 10',
);

和功能

echo (currently_should_play("00:05", $times) === 'Programme 1' ? 'Ok 1' : 'Not Ok 1') . PHP_EOL;

如果第一次小于第二次它应该运行第一次并且如果它等于精确值而不是它的运行甚至......

上面的函数调用应该与00:00匹配并打印'ok'

让我们假设另一个例子

echo (currently_should_play("00:58", $time) === 'Programme 2' ? 'Ok 2' : 'Not Ok 2') . PHP_EOL;

它应该与第二个值匹配，因为它与程序 2 匹配...

请提供一些解决方案..

我的函数代码在这里，我从数组中获取键和值

function currently_should_play($current_time, array $times) {
   foreach ($times as $time => $programme) {
    echo $time;
    echo $programme."<br/>";

   }
}

Answer 1

function currently_should_play($current_time, array $times) {
  $s=size($times);
  while($s-->0){
   if($times[$s]==$current_time){
    return $times[$s];
   }elseif($times[$s-1]==$current_time){
    return $times[$s-1];
   }elseif($times[$s-1]<$current_time&&$times[$s]>$current_time){
    return $times[$s-1];
   }
 }
 return false;
}