您可以迭代从 2018 年到 2022 年的年份以获取每个目标日期的工作日名称,然后找到匹配年份。
df = pd.DataFrame({'Date': {0: 'Sun, Dec 30',
1: 'Mon, Dec 31'}})
for col in range(2018, 2022):
df[col] = '%s' % col + df['Date'].str.split(',').str[-1]
df[col] = pd.to_datetime(df[col], format='%Y %b %d').dt.strftime('%a, %b %d')
dfn = df.set_index('Date').stack().reset_index()
cond = dfn['Date'] == dfn[0]
obj = dfn[cond].set_index('Date')['level_1'].rename('year')
结果:
print(obj)
Date
Sun, Dec 30 2018
Mon, Dec 31 2018
Name: year, dtype: int64
print(df.join(obj, on='Date'))
Date 2018 2019 2020 2021 year
0 Sun, Dec 30 Sun, Dec 30 Mon, Dec 30 Wed, Dec 30 Thu, Dec 30 2018
1 Mon, Dec 31 Mon, Dec 31 Tue, Dec 31 Thu, Dec 31 Fri, Dec 31 2018
df_result = obj.reset_index()
df_result['Date_new'] = df_result['Date'].str.split(',').str[-1] + ' ' + df_result['year'].astype(str)
print(df_result)
Date year Date_new
0 Sun, Dec 30 2018 Dec 30 2018
1 Mon, Dec 31 2018 Dec 31 2018