【发布时间】:2017-09-05 06:26:56
【问题描述】:
我在 java 中创建了一个程序,用于将 1000 个随机数输入两个不同的数据库,一个用于奇数,一个用于偶数。代码执行良好,但执行需要将近一分钟。如何最大限度地减少执行时间?
代码如下:
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.util.Random;
public class Test1 extends Thread {
public static void main(String[] args) throws ClassNotFoundException, SQLException {
long start = System.currentTimeMillis();
int evencount = 0;
int oddcount = 0;
int breakcon = 0;
int breakcon1 = 0;
Class.forName("com.mysql.jdbc.Driver");
Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/db1" + "?useSSL=false", "root",
"1234");
Connection conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/db2" + "?useSSL=false", "root",
"1234");
try {
Class.forName("com.mysql.jdbc.Driver");
for (int n = 1; n <= 1000; n++) {
Random r = new Random();
int val = r.nextInt(100000);
if (val % 2 == 0) {
PreparedStatement ps = con.prepareStatement(" insert into try values (?)");
ps.setInt(1, val);
ps.executeUpdate();
ps.addBatch();
breakcon = breakcon + 1;
if (breakcon % 500 == 0 || breakcon == val)
ps.executeBatch();
evencount++;
} else {
try {
Class.forName("com.mysql.jdbc.Driver");
PreparedStatement ps3 = conn.prepareStatement(" insert into try1 values (?)");
ps3.setInt(1, val);
ps3.executeUpdate();
ps3.addBatch();
breakcon1 = breakcon1 + 1;
if (breakcon1 % 500 == 0 || breakcon1 == val)
ps3.executeBatch();
oddcount++;
}
catch (Exception e2) {
System.out.println(e2);
}
}
}
}
catch (Exception e) {
System.out.println(e);
}
long end = System.currentTimeMillis();
NumberFormat formatter = new DecimalFormat("#0.00000");
System.out.println("Execution time is " + formatter.format((end - start) / 1000d) + " seconds");
System.out.println(oddcount + evencount);
}
}
【问题讨论】:
-
我会看看 SQL 批处理。
-
@JoeC 我该怎么做?请解释
-
这类问题最好在Code Review 提问。因为它是关于改进运行代码
-
@Jens 宁愿完全删除
Class.forName()...这是过去的真正爆炸。
标签: java execution-time