【发布时间】:2021-08-26 11:27:17
【问题描述】:
我在 Laravel Livewire 项目中有一个表单,并尝试从数据库中搜索和选择用户。当我搜索用户时,搜索结果中的用户,但没有选择。此外,仅显示页面刷新没有错误。我的代码如下: I'm trying this
livewire 组件视图
<div class="col-md-4">
<div class="form-group row">
<label class="control-label col-md-2 col-sm-2">Select User</label>
<div class="col-md-10 col-sm-10 ">
<div>
<select wire:model="user_id" class="form-control" name="user_id" required>
<option></option>
@foreach($users as $user)
<option value="{{$user->id}}">{{$user->username}} : {{ $user->fullname }}</option>
@endforeach
</select>
</div>
<div style="position:relative">
<input wire:model.debounce.500ms="inputsearchuser" class="form-control relative" type="text"
placeholder="search..."/>
</div>
<div style="position:absolute; z-index:100">
@if(strlen($inputsearchuser)>2)
@if(count($searchusers)>0)
<ul class="list-group">
@foreach($searchusers as $searchuser)
<li class="list-group-item list-group-item-action">
<spanwire:click
="selectuser({{$searchuser->id}},{{$searchuser->terms}})">{{$searchuser->username}}
: {{$searchuser->fullname}}</span>
</li>
</ul>
@endforeach
@else
<li class="list-group-item">User Not Found...</li>
@endif
@endif
</div>
</div>
</div>
</div>
livewire 组件
class MyLiveWireComponent extends Component
{
public $j = 1;
public $users = [];
public $inputsearchuser = '';
public $user_id;
public function selectuser($user_id,$terms)
{
$this->user_id = $user_id;
$this->terms = $terms;
$this->inputsearchuser = '';
}
public function render()
{
$searchusers = [];
if (strlen($this->inputsearchuser) >= 2) {
$searchusers = User::Where('username', 'LIKE', '%' . $this->inputsearchuser . '%')
->get();
}
return view('livewire.admin.orders.add-order', ['searchusers' => $searchusers])->layout('components.layouts.admin');
}
}
【问题讨论】:
-
dd($searchusers) 在运行查询后检索一些数据?
-
是的,我得到了搜索结果
-
为什么不使用 selec2 来实现呢?
-
livewire 冲突一些 select2