根据另一个数组的奇偶索引元素创建数组答案

【问题标题】：create arrays based on elements of odd and even indexes of another array根据另一个数组的奇偶索引元素创建数组
【发布时间】：2019-08-06 19:03:14
【问题描述】：

我想用sentence 数组的奇偶索引 填充两个数组（sentences 和 links）：

这是我尝试但没有成功的方法：

     let link_sentence = ">60-1> don't you worry >6-2> I gonna make sure that >16-32> tomorrow is another great day"; // 
                 
        let sentence =  link_sentence.split(">")
        let sentences= []
        let links = []
        for(let i = 0; i < sentence.length; i += 2) {  
        
            sentences.push(sentence[i]);
        }
        console.log(sentences)

预期的输出应该是：

//let links = ["60-1", "6-2", "16-32"];
//let sentences = ["don't you worry", "I gonna make sure that", "tommorow is  another great day"];

【问题讨论】：

sentences 看起来非常接近正确，而您甚至没有尝试计算 links。
我不知道应该如何计算链接，是的，如果句子看起来不太接近正确，我永远不会寻求帮助

标签： javascript

【解决方案1】：

您可以匹配部分并在拆分时省略空字符串。

var link_sentence = ">60-1> don't you worry >6-2> I gonna make sure that >16-32> tomorrow is another great day",
    sentences = [],
    links = [];

link_sentence
    .match(/\>[^>]+/g)
    .reduce(
        (r, s, i) => (r[i % 2].push(s.slice(1)), r),
        [links, sentences]
    );

console.log(sentences);
console.log(links);

.as-console-wrapper { max-height: 100% !important; top: 0; }

【讨论】：

让人们头疼 :) 但一如既往地做得很好，尼娜 ^_^

【解决方案2】：

您的初始尝试很接近，如果您稍微修改您的 for 循环，您可以获得您想要的结果。

// remove first value from the array if the value is empty
if (!sentence[0]) {
    sentence.shift();
}

for(let i = 0; i < sentence.length; i++) {  
    if (i % 2 === 0) {
        links.push(sentence[i]);
    } else {
        sentences.push(sentence[i]);
    }
}

【讨论】：

除了句子以>开头，因为第一个链接是空的，然后是一个链接，然后是一个句子，所以你的索引会不正确:)
我认为这很好，因为 OP 似乎理解其背后的逻辑 :) 唯一的缺点可能是链接和句子会“断开连接”

【解决方案3】：

这是一个使用Array.prototype.reduce的简单解决方案：

const sentence = ">60-1> don't you worry >6-2> I gonna make sure that >16-32> tomorrow is another great day".split(">")

const {links, sentences} = sentence.reduce((acc, val, index) => {
  acc[index % 2 === 0 ? 'links' : 'sentences'].push(val);
  return acc;
}, {
  links: [],
  sentences: []
});

console.log(links, sentences);

【讨论】：

【解决方案4】：

你可以这样做：

const link_sentence = ">60-1> don't you worry >6-2> I gonna make sure that >16-32> tomorrow is another great day"
const sentence =  link_sentence.split(">")
const sentences = []
const links = []

sentence.forEach((el, idx) => {
  if (idx % 2 === 0) {
    // if even
    sentences.push(el)
  } else {
    // if odd
    links.push(el)
  }
})

【讨论】：

【解决方案5】：

你可以使用：

let link_sentence = ">60-1> don't you worry >6-2> I gonna make sure that >16-32> tomorrow is another great day"; // 
                 
let sentence =  link_sentence.split(">")
let sentences = []
let links = []

// removing the first element of array: [""]
sentence.splice(0, 1)

// iterating sentence
sentence.forEach((item, index) => {
  // if the index is even push to links, else push to sentences
  if (index % 2 === 0) {
    links.push(item)
  } else {
    // trim white spaces
    sentences.push(item.trim())
  }
})
console.log(links)
console.log(sentences)

【讨论】：