使用代码创建网络接入点名称，

Question

我想通过代码创建 APN，Android SDK 中是否有任何支持，我尝试了很多但没有成功，我找到了一些与此相关的信息 http://blogs.msdn.com/b/zhengpei/archive/2009/10/13/managing-apn-data-in-google-android.aspx 我使用此参考创建了一个类但无法做到任何东西，任何人都可以为此提供解决方案吗？？？？ 谢谢

Answer 1

我会举几个例子：

获取默认 APN 信息：

//path to APN table
final Uri APN_TABLE_URI = Uri.parse("content://telephony/carriers");

//path to preffered APNs
final Uri PREFERRED_APN_URI = Uri.parse("content://telephony/carriers/preferapn");

//receiving cursor to preffered APN table
Cursor c = getContentResolver().query(PREFERRED_APN_URI, null, null, null, null);

//moving the cursor to beggining of the table
c.moveToFirst();

//now the cursor points to the first preffered APN and we can get some
//information about it
//for example first preffered APN id    
int index = c.getColumnIndex("_id");    //getting index of required column
Short id = c.getShort(index);           //getting APN's id from

//we can get APN name by the same way
index = c.getColumnIndex("name");
String name = c.getString(index); 

//and any other APN properties: numeric, mcc, mnc, apn, user, server,
//password, proxy, port, mmsproxy, mmsport, mmsc, type, current

定义新的 APN：

//first we have to create a new row in APN table
int id = -1;
ContentResolver resolver = this.getContentResolver();
ContentValues values = new ContentValues();

//create value, you can define any other APN properties in the same way
values.put("name", "Your APN Name");    //choose APN name, like 3G Orange
values.put("apn", "Your APN address");  //choose APN address, like cellcom.wapu.co.il

//now we have to define APN setting page UI. You have to get operator numeric property
//you can obtain it from TelephonyManager.getNetworkOperator() method
values.put("mcc", "your operator numeric high part");  //for example 242
values.put("mnc", "your operator numeric low part");   //for example 501
values.put("numeric", "your operator numeric");        //for example 242501

Cursor c = null;
try
{
    //insert new row to APN table
    Uri newRow = resolver.insert(APN_TABLE_URI, values);
    if(newRow != null)
    {
        c = resolver.query(newRow, null, null, null, null);

        //obtain the APN id
        int index = c.getColumnIndex("_id");
        c.moveToFirst();
        id = c.getShort(index);
    }
}
catch(Exception e)
{
}

//now after we created a new APN in APN table
//and APN's ID stored in id variable (or -1 if any troubles was happaned)
//we can define a new APN as default
values = new ContentValues();
values.put("apn_id", id); 

try
{
    resolver.update(PREFERRED_APN_URI, values, null, null);
}
catch (Exception e)
{
}

所以，它必须工作，但如果不能 - 告诉我，我会尝试检查问题。

Answer 2

@Borg8 谢谢，你帮了我很多，这是我错过的，一开始我在 UI 列表中看不到新的 APN。 我在@DeepSan 上面的链接here 上找到了我的答案。

要查看我刚刚在 ** emaltor ** UI 中创建的新 APN，我使用了 310260 数字编号

// TelephonyProperties;
    values.put("mcc", "310");
    values.put("mnc", "260");
    values.put("numeric", "310260");

为了在我的设备（Galaxy）上看到它，我使用了 TelephonyManager：

  TelephonyManager tel = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
    String networkOperator = tel.getNetworkOperator();
    int mcc = 0;
    int mnc = 0;
    if (networkOperator != null) {
          mcc = Integer.parseInt(networkOperator.substring(0, 3));
          mnc = Integer.parseInt(networkOperator.substring(3));
    }

   // TelephonyProperties;
    values.put("mcc", mcc );
    values.put("mnc", mnc );
    values.put("numeric",networkOperator);

现在我可以在 UI 上看到新的 APN。