Python 键盘输入答案

【问题标题】：Python keyboard inputPython 键盘输入
【发布时间】：2021-02-19 09:19:09
【问题描述】：

我是初学者，如何创建一个键列表，以便Presskey 随机按下列表中的一个键。我需要一个小键盘键列表，他的键盘键[在此处输入链接描述 http://web-old.archive.org/web/20190801085838/http://www.gamespp.com/directx/directInputKeyboardScanCodes.html

import ctypes
import time
import random

from pynput.keyboard import Controller
SendInput = ctypes.windll.user32.SendInput

# C struct redefinitions 
PUL = ctypes.POINTER(ctypes.c_ulong)
class KeyBdInput(ctypes.Structure):
    _fields_ = [("wVk", ctypes.c_ushort),
                ("wScan", ctypes.c_ushort),
                ("dwFlags", ctypes.c_ulong),
                ("time", ctypes.c_ulong),
                ("dwExtraInfo", PUL)]

class HardwareInput(ctypes.Structure):
    _fields_ = [("uMsg", ctypes.c_ulong),
                ("wParamL", ctypes.c_short),
                ("wParamH", ctypes.c_ushort)]

class MouseInput(ctypes.Structure):
    _fields_ = [("dx", ctypes.c_long),
                ("dy", ctypes.c_long),
                ("mouseData", ctypes.c_ulong),
                ("dwFlags", ctypes.c_ulong),
                ("time",ctypes.c_ulong),
                ("dwExtraInfo", PUL)]

class Input_I(ctypes.Union):
    _fields_ = [("ki", KeyBdInput),
                 ("mi", MouseInput),
                 ("hi", HardwareInput)]

class Input(ctypes.Structure):
    _fields_ = [("type", ctypes.c_ulong),
                ("ii", Input_I)]

# Actuals Functions

def PressKey(hexKeyCode):
    extra = ctypes.c_ulong(0)
    ii_ = Input_I()
    ii_.ki = KeyBdInput( 0, hexKeyCode, 0x0008, 0, ctypes.pointer(extra) )
    x = Input( ctypes.c_ulong(1), ii_ )
    ctypes.windll.user32.SendInput(1, ctypes.pointer(x), ctypes.sizeof(x))

def ReleaseKey(hexKeyCode):
    extra = ctypes.c_ulong(0)
    ii_ = Input_I()
    ii_.ki = KeyBdInput( 0, hexKeyCode, 0x0008 | 0x0002, 0, ctypes.pointer(extra) )
    x = Input( ctypes.c_ulong(1), ii_ )
    ctypes.windll.user32.SendInput(1, ctypes.pointer(x), ctypes.sizeof(x))


# directx scan codes http://www.gamespp.com/directx/directInputKeyboardScanCodes.html
while (True):
    delay = random.uniform(0, 0.11)
    PressKey(0x4F)
    time.sleep(delay)
    ReleaseKey(0x4F)
    time.sleep(delay)

【问题讨论】：

标签： python keyboard

【解决方案1】：

我使用pyautogui 模块为您提供了一个简单的解决方案：

import pyautogui
import random
list_of_keys = ["num0", "num1", "num2", "num3", "num4", "num5", "num6", "num7", "num8", "num9"]
# or you can generate the keys using: ["num"+str(i) for i in range(10)]
key = random.choice(list_of_keys) # select random key from the list
pyautogui.press(key)

基本上我创建了 numpad-keys 列表（您可以查看有关按键 here 的 pyautogui 文档），使用 random.choice(list) 从列表中选择随机键并使用 pyautogui.press(key) 按下键。
祝你好运！

【讨论】：