如何在strings.xml（res/value）Android Studio中引用用户的输入

Question

我关注的是 Developers.Android codelab tutorial。在我了解到的代码中，您可以在 .xml 布局文件中使用@={}（点表示法访问数据类中的数据）来引用数据..

类似的东西；

        <TextView
            ...
            android:text="@={myName.nickname}"
            ...
            />

但我希望能够在字符串中使用多个输入数据，像这样；

    <string name="bio">Hi, @={myName.nickname}.
        I'm Alexia, I love fish.

        The kind that is alive and swims around in an aquarium or river, or a lake, and definitely the ocean.
        Fun fact is that I have several aquariums and also a river.

        I like eating fish, too. Raw fish. Grilled fish. Smoked fish. Poached fish - not so much.
        And sometimes I even go fishing.
        And even less sometimes, I actually catch something.
        Once, when I was camping in Canada, and very hungry, I even caught a large salmon with my hands.

        I\'ll be happy to teach you @={myName.nickname}, how to make your own aquarium.
        But, @={myName.nickname} you should ask someone else about fishing, though, lol.</string>

但是当我运行它时，它只返回@={myName.nickname} 作为@={myName.nickname}，即不是数据，我正在尝试引用，所以请我如何引用strings.xml 值文件。??

感谢您提前提供的帮助...

这是我与此相关的文件，如果您需要任何东西，请告诉我..

数据类：

package com.example.aboutme

data class MyName(var name: String = "", var nickname: String = "")

activity_main.xml;

<layout
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools">

    <data>
        <variable
            name="myName"
            type="com.example.aboutme.MyName" />
    </data>

    <LinearLayout
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:orientation="vertical"
        tools:context=".MainActivity">

        ...

Answer 1

格式化文本：

binding.nameText = context.getString(R.string.bio, myName.nickname)

布局：

<variable
    name="nameText"
    type="String" />
...
<TextView
    ...
    android:text="@{nameText}"
    ...
/>

字符串：

<string name="bio">Hi, %s, I'm Alexia</string>