C++，如何将gcrypt库中gcry_cipher_encrypt的返回值复制到变量中？

Question

在我下面附加的代码中，它使用了 gcry_cipher_encrypt。在代码的末尾，它将 encBuffer 中的内容输出为十六进制值字符串。我需要在 char[]、char* 或 string 之类的变量中创建它并使用它。

根据gcrypt手册encBuffer，函数的第二项应该是一个无符号char*类型的变量。我认为它应该指向一个无符号字符数组。但是当我这样做时：

for(int i = 0; i < txtLength-1;i++){
   cout<<encBuffer[i];
}

我收到大量代码。请问如何从 encBuffer 获取可读内容？非常感谢。

#include <stdio.h>
#include <gcrypt.h>

int main () {
gcry_error_t     gcryError;
gcry_cipher_hd_t gcryCipherHd;
size_t           index;
char * salsaKey = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"; // 32 bytes
char * iniVector = "AAAAAAAA"; // 8 bytes

gcryError = gcry_cipher_open(
    &gcryCipherHd, // gcry_cipher_hd_t *
    GCRY_CIPHER_SALSA20,   // int
    GCRY_CIPHER_MODE_STREAM,   // int
    0);            // unsigned int
if (gcryError)
{
    printf("gcry_cipher_open failed:  %s/%s\n",
           gcry_strsource(gcryError),
           gcry_strerror(gcryError));
    return;
}
printf("gcry_cipher_open worked\n");

gcryError = gcry_cipher_setkey(gcryCipherHd, salsaKey, 32);
if (gcryError)
{
    printf("gcry_cipher_setkey failed:  %s/%s\n",
           gcry_strsource(gcryError),
           gcry_strerror(gcryError));
    return;
}
printf("gcry_cipher_setkey worked\n");

gcryError = gcry_cipher_setiv(gcryCipherHd, iniVector, 8);
if (gcryError)
{
    printf("gcry_cipher_setiv failed:  %s/%s\n",
           gcry_strsource(gcryError),
           gcry_strerror(gcryError));
    return;
}
printf("gcry_cipher_setiv worked\n");

size_t txtLength = 101;
char * encBuffer = malloc(txtLength);
char * textBuffer = malloc(txtLength);
memset(textBuffer, 0, 101);

gcryError = gcry_cipher_encrypt(
    gcryCipherHd, // gcry_cipher_hd_t
    encBuffer,    // void *
    txtLength,    // size_t
    textBuffer,    // const void *
    txtLength);   // size_t
if (gcryError)
{
    printf("gcry_cipher_decrypt failed:  %s/%s\n",
           gcry_strsource(gcryError),
           gcry_strerror(gcryError));
    return;
}
printf("gcry_cipher_decrypt worked\n");

printf("encBuffer = ");
for (index = 0; index<txtLength-1; index++)
    printf("%02X", (unsigned char)encBuffer[index]);
printf("\n");
return 0;
}

Answer 1

我使用 malloc 制作了以下函数（因为您的代码确实如此）。

char *buffer2hex(char *encBuffer, int txtLength){
    char *encHexText = (char *)malloc(txtLength*2+1), 
         *eht = encHexText;
    for (int i = 0; i < txtLength; i++){
        int c = (unsigned char)encBuffer[i];
        #define tohex(n) ((n)>9?(n)-10+'A':(n)+'0')
        *eht++ = tohex(c>>4);
        *eht++ = tohex(c&0xf);
        #undef tohex
    }
    *eht = '\0';
    return encHexText; 
}

在你的方法结束时，你可以这样调用它：

    char *hex = buffer2hex(encBuffer, txtLength);
    printf("%s\n", hex); // Use it
    free(hex);           // and free it!