【发布时间】：2015-03-15 13:58:08
【问题描述】：
我有一个向 php doc 发送信息的表单。测试时，我提交并显示数组，但不会转到电子邮件地址。
<?php require_once("/includes/fbcheader.php");
?>
<div class="comments">
<h3> We Welcome All Comments </h3>
<form action="/php/contact-send.php" method="post"
id="contact-form" class="form">
<p class="input-block">
<label for="form-name" >Name</label>
<input type="text" value name="name" id="form-name"
autofocus placeholder="Please enter name" required>
</p>
<p class="input-block">
<label for="form-email" >Email</label>
<input type="email" value name="email" id="form-email"
required placeholder="Please enter E-Address">
<input type="hidden" value name="age" id="age">
</p>
<p class="input-block">
<label for="form-subject" >Subject</label>
<input type="text" value name="subject" id="form-subject"
required placeholder="Please enter subject">
</p>
<p class="textarea-block">
<label for="form-message">Comment</label>
<textarea name="message" id="form-message"
cols="70" rows="10"></textarea>
</p>
<div class="clear"></div>
<input type="hidden" name="firstname" id="firstname">
<input type="submit" value="Send" id="form-submit">
<p class="hide" id="response"></p>
<div class="hide">
<label for="spam-check">Do not fill out this field</label>
<input name="spam-check" type="text" value id="spam-check">
</div>
</form>
</div>
</body>
</html>
这是发送的php执行代码
<html>
<head>
<title>Contact-Send</title>
</head>
<body>
<?php
if(null!==($_POST["name"])) {
$name = $_POST["name"];
/* echo "Please enter 'Name'<br />"; */
} else {
$name = "";
}
if(null!==($email = $_POST["email"])) {
$email = $_POST["email"];
/* echo "Please enter 'E_Mail'<br />"; */
} else {
$email = "";
}
if(null!==($email = $_POST["subject"])) {
$form_email = $_POST["subject"];
/* echo "Please enter 'Subject'<br />"; */
} else {
$subject = "";
}
if(null!==($message = $_POST["message"])) {
$message = $_POST["message"];
/* echo "Please enter your message<br />"; */
} else {
$message = "";
}
/*echo "{$name}, {$email}, {$message}";*/
$email_from = '$Email';
$email_subject = "New Form submission";
$email_body = "You have received a new message from the user $name.\n".
"Here is the message:\n $message".
$to = "me@myaddress.com";
?>
<br>
<?php
$headers = "From: $email_from \r\n";
$headers .= "Reply-To: $form_email \r\n";
mail($to,$email_subject,$email_body,$headers);
header("thank-you.html");
?>
</body>
</html>
提交时，我只需获取显示输入字段内容的数组
【问题讨论】：
-
你是什么意思“我只是得到显示输入字段内容的数组”？
-
检查
mail()函数的返回值，你的From头会导致消息失败，你需要在那里使用双引号。实际上根本没有...... -
value name这会导致一些意想不到的结果。 -
@JohnConde - 当我按下提交时，下一页显示输入名称及其内容。例如。数组 ([name] => Jonathan; [email] => JonDoe@abcsite.com; [age] => ;[subject] => test; ...
-
那么你有
<input type="hidden" name="firstname" id="firstname">没有价值也没有参考，所以我不知道你为什么要使用它，对于<input type="hidden" value name="age" id="age">加上，我已经说过关于 @987654328 @.