在 Python 中，Spyne 遇到了很多问题

Question

好吧，这是我的 Python 代码：

#!/usr/bin/env python
from spyne import Application, rpc, ServiceBase, Unicode
from lxml import etree
from spyne.protocol.soap import Soap11
from spyne.server.wsgi import WsgiApplication
# Wsgi это Web server Getewap Interface - стандар взаимодействия с питон программой и серверо где он работает

class Soap(ServiceBase):
    @rpc(Unicode, _return=Unicode)
    def Insoap(ctx, words):
        print("Connection detected: ", etree.tostring(ctx.in_document))
        ww = str(words).capitalize()
        return ww

app = Application([Soap], tns='Capitalize', in_protocol=Soap11(validator='lxml'), out_protocol=Soap11())
application = WsgiApplication(app) # Важна названия переменной, иначе сервер не поймет


if __name__ == '__main__':
    from wsgiref.simple_server import make_server
    server = make_server('localhost', 8002, application)
    server.serve_forever()

但是得到这个错误，有什么问题？我应该怎么做才能解决？请帮我解决这个问题

Traceback (most recent call last):
  File "C:/Users/David374/PycharmProjects/untitled8/venv/test.py", line 3, in <module>
    from spyne import Application, rpc, ServiceBase, Iterable, UnsignedInteger, \
  File "C:\Users\David374\PycharmProjects\untitled8\venv\lib\site-packages\spyne\__init__.py", line 63, in <module>
    from spyne.server import ServerBase, NullServer
  File "C:\Users\David374\PycharmProjects\untitled8\venv\lib\site-packages\spyne\server\__init__.py", line 23, in <module>
    from spyne.server.null import NullServer
  File "C:\Users\David374\PycharmProjects\untitled8\venv\lib\site-packages\spyne\server\null.py", line 69
    self.service = _FunctionProxy(self, self.app, async=False)
                                                  ^
SyntaxError: invalid syntax

Answer 1

async 是 Python 3.7+ 中的保留关键字，如果您想将其与Python 3.7+。

要么将 Spyne 更新为 spyne-2.13.2-alpha，要么使用 Python 3.6 或更低版本。

来源：

• https://docs.python.org/3/whatsnew/3.7.html
• https://pypi.org/project/spyne/2.13.2a0/