【问题标题】:invoking url with RESTTEmplate and binding response with JAXB使用 RESTTEmplate 调用 url 并使用 JAXB 绑定响应
【发布时间】:2013-01-03 17:31:10
【问题描述】:

使用此代码,我有一个要调用的 url 当我使用导航器调用此 url 时,我有一个 xml 响应,我想在一个名为 Response 的对象中检索它,该对象由 JAXB 注释

@Test
public void testRestTemplate()
{
    List<MediaType> acceptableMediaTypes = new ArrayList<MediaType>();
    acceptableMediaTypes.add(new MediaType("application", "xml"));
    HttpHeaders requestHeaders = new HttpHeaders();
    requestHeaders.setAccept(acceptableMediaTypes);
    HttpEntity<?> requestEntity = new HttpEntity<Object>(requestHeaders);
    RestTemplate restTemplate = new RestTemplate();
    restTemplate.setRequestFactory(new HttpComponentsClientHttpRequestFactory());
      String url= "http://1.......bf93af6" ; 

      ResponseEntity<ListResponse> responseEntity = restTemplate.exchange(url ,HttpMethod.GET, requestEntity, ListResponse.class);
      ListBigBlueButtonResponse listResponses = responseEntity.getBody(); 

}

所以我有这个失败跟踪:

org.springframework.web.client.RestClientException: Could not extract response: no suitable HttpMessageConverter found for response type [class com.alpha.vconf.test.ListResponse] and content type [text/xml;charset=utf-8]
at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:107)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:688)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:674)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:492)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:447)
at org.springframework.web.client.RestTemplate.exchange(RestTemplate.java:394)
at com.alpha.vconf.test.VisioConfMangerTest.testRestTemplate(VisioConfMangerTest.java:43)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.runners.BlockJUnit4ClassRunner.runNotIgnored(BlockJUnit4ClassRunner.java:79)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:71)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:49)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

我可以在使用 JAXB 映射的对象中有任何 xml 响应吗 R:在我的响应对象中,我的响应具有与由@XmlElement 注释的XMLELEMENT 相同的属性,并且该类由@XmlRootElement 注释

【问题讨论】:

    标签: xml rest xml-parsing jaxb resttemplate


    【解决方案1】:

    您收到此异常是因为您没有为 Content-Type application/xml 添加合适的 Http 消息转换器到休息模板,该模板可用于序列化/反序列化对象。默认情况下,rest 模板中有一些消息转换器,但有时需要显式添加一个/多个,如下所示。这里有一些对我有用的东西,可以将 XML 响应反序列化为对象。

    XStreamMarshaller marshaller = new XStreamMarshaller();
    Map<String, Class> aliases = new HashMap<String, Class>();
    aliases.put("person", Person.class); //"person" is root element.This is case sensitive
    marshaller.setAliases(aliases);
    MarshallingHttpMessageConverter converter = new MarshallingHttpMessageConverter(
                marshaller, marshaller);
    List<HttpMessageConverter<?>> converters = new ArrayList<HttpMessageConverter<?>>();
        converters.add(converter);
    template.setMessageConverters(converters);
    HttpEntity request = new HttpEntity(null, headers);
    ResponseEntity<Person> response = template.exchange(url,
                HttpMethod.GET, request, Person.class);
    

    【讨论】:

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