需要SQL查询 | SQL 10g |甲骨文

Question

我的父表如下：

Date        Month   PRICE   product contract_month  Contract_year
7-Jun-17    17-Sep  -79     XYZ     9                2017
7-Jun-17    17-Oct  -75     XYZ     10               2017
7-Jun-17    17-Jul  -92     XYZ     7                2017
7-Jun-17    17-Aug  -90     XYZ     8                2017
7-Jun-17    18-Sep  -95     XYZ     9                2018
7-Jun-17    18-Oct  -96     XYZ     10               2018
7-Jun-17    18-Nov  -97     XYZ     11               2018

正在执行以下查询：

SELECT opr_date,contract,price
                 FROM   table
                 WHERE  date = '07-jun-2017' 
                        AND product = 'XYZ'
                        ANd contract_year = 2017
                        AND contract_month between 1 and 12

我的查询正在提取这个结果：

Date        Month   PRICE
7-Jun-17    17-Sep  -79
7-Jun-17    17-Oct  -75
7-Jun-17    17-Jul  -92
7-Jun-17    17-Aug  -90

但当且仅当该季度的所有三个月都存在时，它才应该填充价格。 在上面的例子中：我们有 6 月和 8 月的价格。因此，第三季度所有 3 个月的价格都存在。所以它应该填充相应的价格。 但是对于第 4 季度，即 Oct,Nov 和 dec (contract_month = 10,11 &12) 月份，仅存在 oct 价格。所以我的查询不应该填充这个价格或者它应该填充为空（因为价格在父表中不存在 nov 和 dec）。

Answer 1

逐年确定季度并计算结果（分组依据，count=3）：

select opr_date,contract,price
  from your_table
 where /* your conditions ...   */
     date = '07-jun-2017'
 and product = 'XYZ'
 and contract_year = 2017
 and contract_month between 1 and 12
/* only rows, where exist 3 rows per quarter */
 and case
   when contract_month between 1 and 3 then
    contract_year * 10 + 1
   when contract_month between 4 and 6 then
    contract_year * 10 + 2
   when contract_month between 7 and 9 then
    contract_year * 10 + 3
   else
    contract_year * 10 + 4
 end in (select quarter
           from (select case
                          when contract_month between 1 and 3 then
                           contract_year * 10 + 1
                          when contract_month between 4 and 6 then
                           contract_year * 10 + 2
                          when contract_month between 7 and 9 then
                           contract_year * 10 + 3
                          else
                           contract_year * 10 + 4
                        end as quarter
                   from your_table)
          group by quarter
         having count(*) = 3);