在红移中进行不同汇总的更好方法？

Question

编写一个查询的最佳方法是在 redshift 上对不同离散时间范围内的不同计数进行汇总？

例如，如果您为各个组织的潜在客户收集了一些电话号码，并想了解每周、每月、每季度等创建了多少不同的电话号码......最好的方法是什么？

这是我能想到的最好的：

SELECT
  organization,
  sum(weekly) as weekly,
  sum(monthly) as monthly,
  sum(quarterly) as quarterly,
  sum(yearly) as yearly
FROM (
    SELECT 
      organization,
      COUNT(DISTINCT phoneNumber) as weekly,
      null as monthly,
      null as quarterly,
      null as yearly
    FROM Lead
    WHERE createdAt >= current_date - interval '7 days'
    GROUP BY organization

      UNION ALL

    SELECT
      organization,
      null as weekly,
      COUNT(DISTINCT phoneNumber) as monthly,
      null as quarterly,
      null as yearly
    FROM Lead
    WHERE createdAt >= current_date - interval '1 month'
    GROUP BY organization

        UNION ALL

    SELECT
      organization,
      null as weekly,
      null as monthly,
      COUNT(DISTINCT phoneNumber) as quarterly,
      null as yearly
    FROM Lead
    WHERE createdAt >= current_date - interval '3 months'
    GROUP BY organization

        UNION ALL

    SELECT
      organization,
      null as weekly,
      null as monthly,
      null as quarterly,
      COUNT(DISTINCT phoneNumber) as yearly
    FROM Lead
    WHERE createdAt >= current_date - interval '1 year'
    GROUP BY organization
) GROUP BY organization

有什么方法可以让查询更快/更容易理解？

Answer 1

如果我理解正确，您只需使用条件聚合：

SELECT organization,
       COUNT(DISTINCT CASE WHEN created_at >= current_date - interval '7 day' THEN phoneNumber END) as weekly,
       COUNT(DISTINCT CASE WHEN created_at >= current_date - interval '1 month' THEN phoneNumber END) as monthly,
       COUNT(DISTINCT CASE WHEN created_at >= current_date - interval '3 month' THEN phoneNumber END) as quarterly,
       COUNT(DISTINCT CASE WHEN created_at >= current_date - interval '1 year' THEN phoneNumber END) as yearly
FROM Lead
WHERE createdAt >= current_date - interval '1 year'
GROUP BY organization;