ES6 导出模板生成器

Question

使用 CommonJS，我可以执行以下操作：

generator.js:

module.exports = (...args) => ({
  create: makeCreate(...args),
  remove: makeRemove(...args),
});

model.js:

const generate = require('generator.js');

module.exports = generate('my-model');

use.js:

const { create, remove } = require('model.js');

module.exports = {
  doCreate: () => create('something'),
  doRemove: () => remove('something else'),
};

使用 ES6 模块，我可以重构如下：

generator.mjs:

export default (...args) => ({
  create: makeCreate(...args),
  remove: makeRemove(...args),
});

model.mjs:

import generate from 'generator.mjs';

export default generate('my-model');

use.mjs:

import model from 'model.mjs';

export const doCreate = () => model.create('something');
export const doRemove = () => model.remove('something else');

但是，model.mjs 导出自身的方式意味着我不能这样做：

use.mjs:

import { create, remove } from 'model.mjs';

export const doCreate = () => create('something');
export const doRemove = () => remove('something else');

我想不出一种方法来简明地定义 generator.mjs 和 model.mjs 中的导出以使上述成为可能。可以吗？

Answer 1

替代方案：

你可以在use.mjs做这样的事情

import model from 'model.mjs';

const {create, remove} = model;

export const doCreate = () => create('something');
export const doRemove = () => remove('something else');

另一种解决方案是：

在model.mjs

import generate from "./generator.js";

export const { create, remove } = generate("my-model");

在use.mjs

import { create, remove } from "./model.js";

export const doCreate = () => create("something");
export const doRemove = () => remove("something else");