如何删除 JSON 对象的键中的空格答案

【问题标题】：How to remove space in keys of a JSON object如何删除 JSON 对象的键中的空格
【发布时间】：2016-11-25 11:52:16
【问题描述】：

我有如下输出：

output = {
  "New Classroom": [{
    "Name": "Apple",
    "Age": "6",
    "Percentage": "24.00%"
  }, {
    "Name": "Orange",
    "Age": "5",
    "Percentage": "9.88%"
  }, {
    "Name": "Green",
    "Age": "2",
    "Percentage": "27.27%"
  }, {
    "Name": "Grey",
    "Age": "6",
    "Percentage": "12.63%"
  }]
}

如何将New Classroom 替换为NewClassroom 并且新教室并不总是“新教室”。它可能是不同的文本

ob = JSON.parse(output);

alert(Object.keys(ob))

当我这样做时，我将Newclassroom 作为密钥

【问题讨论】：

标签： javascript

【解决方案1】：

您可以遍历收到的对象中的顶级属性名称，检测带有空格的任何内容，然后删除空格。（您不需要，它们是完全有效的属性名称，但如果您愿意，可以。）

var output = { "New Classroom": [{"Name": "Apple","Age": "6","Percentage": "24.00%"},{"Name": "Orange","Age": "5","Percentage": "9.88%"},{"Name": "Green","Age": "2","Percentage": "27.27%"},{"Name": "Grey","Age": "6","Percentage": "12.63%"}]};
var name, newName;
// Loop through the property names
for (var name in output) {
  // Get the name without spaces
  newName = name.replace(/ /g, "");
  // If that's different...
  if (newName != name) {
    // Create the new property
    output[newName] = output[name];
    // Delete the old one
    delete output[name];
  }
}
console.log(output);

请注意，在对象上使用delete 会降低后续属性查找的性能。 99.99% 的时间，这没关系。如果这对您来说很重要，请创建一个 new 对象而不是就地修改它：

var output = { "New Classroom": [{"Name": "Apple","Age": "6","Percentage": "24.00%"},{"Name": "Orange","Age": "5","Percentage": "9.88%"},{"Name": "Green","Age": "2","Percentage": "27.27%"},{"Name": "Grey","Age": "6","Percentage": "12.63%"}]};
var name, newName;
var newOutput = {};
// Loop through the property names
for (var name in output) {
  // Get the name without spaces
  newName = name.replace(/ /g, "");
  
  // Copy the property over
  newOutput[newName] = output[name];
}
console.log(newOutput);

【讨论】：

所以如果Percentage 有一些空格，这将不起作用？
@Mahi：问题不是我的印象。不，它不会，因为我们只处理顶级对象。当然，相同的主体可以应用于从属数组中的对象...

【解决方案2】：

使用Object.keys获取对象的所有键
使用String#replace 替换String 中的字符

var obj = {
  "New Classroom": [{
    "Name": "Apple",
    "Age": "6",
    "Percentage": "24.00%"
  }, {
    "Name": "Orange",
    "Age": "5",
    "Percentage": "9.88%"
  }, {
    "Name": "Green",
    "Age": "2",
    "Percentage": "27.27%"
  }, {
    "Name": "Grey",
    "Age": "6",
    "Percentage": "12.63%"
  }]
};

Object.keys(obj).forEach(function(key) {
  var replaced = key.replace(' ', '');
  if (key !== replaced) {
    obj[replaced] = obj[key];
    delete obj[key];
  }
});
console.log(obj);

注意：只考虑一次出现的空格，如果space出现多次，则可以使用RegEx！

【讨论】：

使用正则表达式替换，否则只替换第一个空格。

【解决方案3】：

循环进入json的每个键，然后解析。

尝试正则表达式

var word = "New Classroom"
word = word.replace(/\s/g, '');
console.log(word)

【讨论】：