比较两个对象并创建新对象答案

【问题标题】：Compare two objects and create new object比较两个对象并创建新对象
【发布时间】：2021-11-29 12:45:18
【问题描述】：

我有两个对象如下：

var1 = {
    "ELEMENT1": [1110,1111],
    "ELEMENT2": ["909"],
    "ELEMENT3": ["910"]
}

var2 =  {
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    },
    {
        "ID":912,
        "NAME":"ELEMENT3",
        "DETAILS":"FUTURE"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    },
    {
        "ID": 910,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1112,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1113,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }]
}

在比较 var1 和 var2 之后，我正在尝试创建第三个对象。第三个对象应该只包含那些存在于var1 中的ID。

第三个对象应该如下所示：

{
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }
    ]
}

【问题讨论】：

标签： javascript ecmascript-6

【解决方案1】：

应该这样做：

var var1 = {
    "ELEMENT1": ["1110","1111"],
    "ELEMENT2": ["909"],
    "ELEMENT3": ["910"]
}

var var2 =  {
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    },
    {
        "ID":912,
        "NAME":"ELEMENT3",
        "DETAILS":"FUTURE"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    },
    {
        "ID": 910,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1112,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1113,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }]
}

var obj = {};
Object.keys(var2).forEach((item) => {
  var2[item].forEach((subItem) => {
    if(var1[item].indexOf(`${subItem.ID}`) > -1) {
      obj[item] = [...(obj[item] ?? []), subItem]
    }
  })
});

console.log(obj);

【讨论】：

【解决方案2】：

您可以循环遍历 var2 和 filter IDs 其中 var1 includes 并将过滤后的道具分配给新对象：

let var1 = {
  ELEMENT1: [1110, 1111],
  ELEMENT2: [909],
  ELEMENT3: [910],
}

let var2 = {
  ELEMENT3: [
    { ID: 910, NAME: 'ELEMENT3', DETAILS: 'CURRENT' },
    { ID: 912, NAME: 'ELEMENT3', DETAILS: 'FUTURE' },
  ],
  ELEMENT2: [
    { ID: 909, NAME: 'ELEMENT2', DETAILS: 'OUTAGE' },
    { ID: 910, NAME: 'ELEMENT2', DETAILS: 'OUTAGE' },
  ],
  ELEMENT1: [
    { ID: 1110, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1111, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1112, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1113, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
  ],
}

const result = {}

for (let key in var2) {
  result[key] = var2[key].filter(o => var1[key]?.includes(o.ID))
}

console.log(JSON.stringify(result, null, 2))

【讨论】：