检查对象数组中的每个对象是否包含另一个数组中的值（JavaScript）

Question

如果我有以下对象数组：

    const movies = [
        {
            movieTitle: "The House That Jack Built",
            movieGenre: "Thriller",
            movieDirector: "Lars Von Trier",
            movieStarring: "Matt Dillon, Uma Therman",
        },
        {
            movieTitle: "Mother!",
            movieGenre: "Thriller",
            movieDirector: "Darren Aronofsky",
            movieStarring: "Jennifer Lawrence",
        },
        {
            movieTitle: "Hot Fuzz",
            movieGenre: "Comedy",
            movieDirector: "Edgar Wright",
            movieStarring: "Simon Pegg",
        }
    ]

还有以下数组：

const filters = ["Jennifer Lawrence", "Comedy"]

如何创建一个新数组，其中仅包含具有 filters 数组中的值的对象（在本例中为最后 2 个）？

谢谢！

Answer 1

使用filter、some 和Object.values：

const movies  = [{movieTitle:"The House That Jack Built",movieGenre:"Thriller",movieDirector:"Lars Von Trier",movieStarring:"Matt Dillon, Uma Therman"},{movieTitle:"Mother!",movieGenre:"Thriller",movieDirector:"Darren Aronofsky",movieStarring:"Jennifer Lawrence"},{movieTitle:"Hot Fuzz",movieGenre:"Comedy",movieDirector:"Edgar Wright",movieStarring:"Simon Pegg"}];
const filters = ["Jennifer Lawrence", "Comedy"];

const res = movies.filter(
  movie => Object.values(movie).some(v => filters.includes(v))
);

console.log(res);