【发布时间】:2016-05-24 22:56:54
【问题描述】:
我正在制作一张桌子,但只使用 Javascript。我已经做了表格,它显示在控制台上,但我无法让它在页面上可见。我试过appendChild() 和insertBefore() 都不行,也不能让网址可点击。
这是我的代码:
var companies = [
{
id: 1,
name: 'Google',
link: 'http://google.com/'
},
{
id: 2,
name: 'Microsoft',
link: 'http://microsoft.com/'
},
{
id: 3,
name: 'Apple',
link: 'http://apple.com'
}
];
var tbl = document.createElement('table');
var input = document.getElementById('input');
var thead = document.createElement("thead");
var tbody = document.createElement("tbody");
var tr_head = document.createElement("tr");
var th_id = document.createElement("th");
var th_name = document.createElement("th");
var th_link = document.createElement("th");
th_id.textContent = "Id";
th_name.textContent = "Name";
th_link.textContent = "link";
tr_head.appendChild(th_id);
tr_head.appendChild(th_name);
tr_head.appendChild(th_link);
thead.appendChild(tr_head);
for(var i = 0; i < companies.length; i++) {
var tr_body = document.createElement("tr");
var td_id = document.createElement("td");
var td_name = document.createElement("td");
var td_link = document.createElement("td");
// var id = companies[i].id;
// var name = companies[i].name;
// var link = companies[i].link;
td_id.textContent = companies[i].id;
td_name.textContent = companies[i].name;
td_link.textContent = companies[i].link;
tr_body.appendChild(td_id);
tr_body.appendChild(td_name);
tr_body.appendChild(td_link);
tbody.appendChild(tr_body);
}
tbl.appendChild(thead);
tbl.appendChild(tbody);
console.log(tbl);
// input.appendChild(tbl);
【问题讨论】:
-
您是否使用开发人员工具验证该元素已添加到 DOM 中?此外,您似乎正在尝试将表写入
input元素,但这是行不通的。您应该将输入更改为div、section、body等标签并在其上调用appendChild
标签: javascript object url dom html-table