检索 .json 对象并将其存储在变量中答案

【问题标题】：retrieving .json object and storing it in variables检索 .json 对象并将其存储在变量中
【发布时间】：2013-03-18 16:31:21
【问题描述】：

我的 .json 文件是：

{
"links":[
  {source: "algorithms cormen", target: "irodov", type: "default"},
  {source: "algorithms cormen", target: "skienna", type: "default"},
  {source: "irodov", target: "skienna", type: "default"},
  {source: "irodov", target: "algorithms cormen", type: "default"}
],
"data":[
    {node: "algorithms cormen", data: "bible of algos"},
    {node: "irodov", data: "bibile of physics"},
    {node: "skienna", data: "cool book"}
]
}

现在在我的 javascript 文件中，我希望“链接”存储的数据转到链接变量。我想对“数据”做同样的事情我如何实现这一目标？我正在使用 d3.js 库，所以如果这个库中包含一些我可以使用的功能，请提及它们。

【问题讨论】：

var links = JSON.parse(yourjson).links?

标签： javascript json d3.js

【解决方案1】：

只需解析 JSON 并将值分配给变量：

var json; // I am assuming this is populated with your JSON string
var jsonObj = JSON.parse(json);
var links = jsonObj.links;
var data = jsonObj.data;

【讨论】：

【解决方案2】：

将 json 文件更新为（假设您在页面加载时包含 json 文件而不是通过 ajax）

var json-data = { 
     "links":[
         {source: "algorithms cormen", target: "irodov", type: "default"},
         {source: "algorithms cormen", target: "skienna", type: "default"},
         {source: "irodov", target: "skienna", type: "default"},
         {source: "irodov", target: "algorithms cormen", type: "default"}
],
    "data":[
        {node: "algorithms cormen", data: "bible of algos"},
        {node: "irodov", data: "bibile of physics"},
        {node: "skienna", data: "cool book"}
    ]
}

然后访问

var links = json-data.links; 
var data = json-data.data;

【讨论】：