【发布时间】:2020-11-03 19:08:19
【问题描述】:
我想在垂直轴或水平轴上画线时计算距离。它可以显示从 mousedraw 或任何其他方式绘制的距离的旁边。有人可以帮我吗?
var width = 400,
height = 500;
var data = [10, 15, 20, 25, 30];
var svg = d3.select("body")
.append("svg")
.attr("width", width)
.attr("height", height)
.on("mousedown", mousedown)
.on("mouseup", mouseup);
var xscale = d3.scale.linear()
.domain([0, d3.max(data)])
.range([0, width - 100]);
var yscale = d3.scale.linear()
.domain([0, d3.max(data)])
.range([height / 2, 0]);
svg.on("mousemove", function() {
console.log("x - using invert", xscale.invert(d3.mouse(this)[0] - 50));
console.log("y- using invert", yscale.invert(d3.mouse(this)[1] - 10));
});
var x_axis = d3.svg.axis()
.scale(xscale).orient("bottom");
var y_axis = d3.svg.axis()
.scale(yscale).orient("left");;
svg.append("g")
.attr("transform", "translate(50, 10)")
.call(y_axis);
var xAxisTranslate = height / 2 + 10;
svg.append("g")
.attr("transform", "translate(50, " + xAxisTranslate + ")")
.call(x_axis)
function mousedown() {
var m = d3.mouse(this);
line = svg.append("line")
.attr("x1", m[0])
.attr("y1", m[1])
.attr("x2", m[0])
.attr("y2", m[1]);
svg.on("mousemove", mousemove);
}
function mousemove() {
var m = d3.mouse(this);
line.attr("x2", m[0])
.attr("y2", m[1]);
}
function mouseup() {
svg.on("mousemove", null);
}
请检查我现在的实时输出:https://jsfiddle.net/anojansith/m38b5fnp/1/
【问题讨论】:
标签: javascript html jquery web d3.js