【发布时间】:2020-07-29 20:31:58
【问题描述】:
我正在尝试通过 Alert API 将 URL 链接到 TouchableOpacity 组件,这使用户可以选择取消链接或继续前进。但是,当我将该功能分配给 onpress 方法并按下该方法时,它会使我的应用程序崩溃。有解决办法吗?
这是我的代码
import React from 'react';
import { Image, Text, Linking, TouchableOpacity, View,ImageBackground, Alert } from 'react-native'
import styles from './styles';
import { firebase } from '../../firebase/config';
import { auth } from 'firebase';
import {Spacer} from '../spacer';
export default function ProductScreen({navigation}){
const logOutPress = () => {
auth()
.signOut()
.then(() => { navigation.navigate("Login"),
alert('You have signed out')})
}
const yalaPress = () => Alert.alert( "You're about to leave the app",[
{ text: "Cancel",
onPress: ()=> console.log('Cancel Pressed')},
{text: "Ok",
onPress: () => Linking.openURL('http://yalajets.com/')
}],{ cancelable: false } );
return(
<ImageBackground source={require('../../../assets/backgroundCopySilk.jpg')} style={styles.backgroundImage}>
<View style={styles.container}>
<TouchableOpacity style={styles.button}>
<Text style={styles.buttonText}>Luxury Commercial Lawn Care</Text>
</TouchableOpacity>
<TouchableOpacity style={styles.button}>
<Text style={styles.buttonText}>Luxury Vehicle Car Detail</Text>
</TouchableOpacity>
<TouchableOpacity style={styles.button}>
<Text style={styles.buttonText}>Luxury Pharmaceuticals</Text>
</TouchableOpacity>
<TouchableOpacity style={styles.button}>
<Text style={styles.buttonText}>Luxury Personal Fitness</Text>
</TouchableOpacity>
<TouchableOpacity style={styles.button}>
<Text style={styles.buttonText}>Luxury Massage with Catch These Hands</Text>
</TouchableOpacity>
<TouchableOpacity
onPress={yalaPress}
style={styles.button}>
<Text style={styles.buttonText}>Luxury Private Flights with Yala Jets</Text>
</TouchableOpacity>
<Spacer/>
<TouchableOpacity
onPress={()=> logOutPress()}>
<Text style={styles.buttonText}>Log Out</Text>
</TouchableOpacity>
</View>
</ImageBackground>
)
};
【问题讨论】:
-
试试 https url
-
不,那没用
标签: react-native