JSON 路径过滤器表达式 SQL Server

Question

我有以下 JSON。我试图构建一个查询来获取名字、姓氏、iPhone 号码和家庭号码。我正在尝试使用 JSON 路径过滤器表达式。它不适合我。

{
  "firstName": "John",
  "lastName" : "doe",
  "age"      : 26,
  "address"  : {
    "streetAddress": "naist street",
    "city"         : "Nara",
    "postalCode"   : "630-0192"
  },
  "phoneNumbers": [
    {
      "type"  : "iPhone",
      "number": "0123-4567-8888"
    },
    {
      "type"  : "home",
      "number": "0123-4567-8910"
    }
  ]
}

使用的查询

DECLARE @jsonInfo NVARCHAR(MAX)

SET @jsonInfo=N'{  

  "firstName": "John",
  "lastName" : "doe",
  "age"      : 26,
  "address"  : {
    "streetAddress": "naist street",
    "city"         : "Nara",
    "postalCode"   : "630-0192"
  },
  "phoneNumbers": [
    {
      "type"  : "iPhone",
      "number": "0123-4567-8888"
    },
    {
      "type"  : "home",
      "number": "0123-4567-8910"
    }
  ]

 }' 
 SELECT
 JSON_VALUE(@jsonInfo,'$.firstName') AS FirstName,
 JSON_VALUE(@jsonInfo,'$.lastName') AS LastName

 --JSON_VALUE(@jsonInfo,'$.phoneNumbers[?(@.type=="iPhone")].number') AS IPhoneNumber,
 --JSON_VALUE(@jsonInfo,'$.phoneNumbers[?(@.type=="home")].number') AS HomeNumber

问候 阿米尔塔拉杰

Answer 1

解析此 JSON 的一种方法是使用 OPENJSON() 和显式架构。 phoneNumbers 是一个 JSON 数组，因此您需要一个额外的 OPENSJON() 调用。

 SELECT 
    j1.firtstName, j1.lastName, j1.streetAddress, j1.city, j1.postalCode,
    j2.*
 FROM OPENJSON(@jsonInfo) WITH (
    firtstName varchar(100) '$.firstName',
    lastName varchar(100) '$.lastName',
    streetAddress varchar(100) '$.address.streetAddress',
    city varchar(100) '$.address.city',
    postalCode varchar(100) '$.address.postalCode',
    phoneNumbers nvarchar(max) '$.phoneNumbers' AS JSON 
 ) j1
 CROSS APPLY (
    SELECT 
       MAX(CASE WHEN [type] = 'iPhone' THEN [number] END) AS iPhone,
       MAX(CASE WHEN [type] = 'home' THEN [number] END) AS home
    FROM OPENJSON(j1.phoneNumbers) WITH (
       type varchar(10) '$.type',
       number varchar(20) '$.number'
    ) 
 ) j2

结果：

firtstName  lastName    streetAddress   city    postalCode  iPhone          ome
John        doe         naist street    Nara    630-0192    0123-4567-8888  0123-4567-8910

当然，您可以使用$.phoneNumbers[x].number 作为path 表达式从$.phoneNumbers JSON 数组中提取每个电话号码（x 是从零开始的索引）：

SELECT 
    j1.firtstName, j1.lastName, j1.streetAddress, j1.city, j1.postalCode,
    j1.number1, j1.number2
 FROM OPENJSON(@jsonInfo) WITH (
    firtstName varchar(100) '$.firstName',
    lastName varchar(100) '$.lastName',
    streetAddress varchar(100) '$.address.streetAddress',
    city varchar(100) '$.address.city',
    postalCode varchar(100) '$.address.postalCode',
    number1 varchar(100) '$.phoneNumbers[0].number',
    number2 varchar(100) '$.phoneNumbers[1].number'
) j1