用于匹配具有多个条件的特定 URL 的正则表达式

Question

我有以下正则表达式模式

const pattern = /^\/(abc|def|something\/thisone|en|ppp){1}/i;

const mat = pattern.exec(myURL);

这里我如何更改上述模式，使其不匹配something/thisone，但是当它后面跟着任何类似这样的参数时：something/thisone/<anystring/number> ..？

试过了：

const pattern = /^\/(abc|def|something\/thisone\/.*|en|ppp){1}/i;

const pattern = /^\/(abc|def|something\/thisone\/.+|en|ppp){1}/i;

似乎没有任何效果..

有效网址：

www.mysite.com/abc/

www.mysite.com/abc

www.mysite.com/def/

www.mysite.com/something/thisone/whatever www.mysite.com/something/thisone/whatever/ www.mysite.com/something/thisone/whatever?u=90

Answer 1

试试这个简单的正则表达式。

let regex = /.*something\/thisone\/.+/g

let string1 = 'something/thisone/acd';
let string2 = 'something/thisone/abc/';
let string3 = 'something/thisone';
let string4 = 'https://somedomain/something/thisone/123';

console.log(string1.match(regex));
console.log(string2.match(regex));
console.log(string3.match(regex));
console.log(string4.match(regex));

Answer 2

你可以试试这个：

const pattern = /^\/(abc|def|something\/thisone\/[0-9a-zA-Z]*){1}/i;

模式[0-9a-zA-Z]* 应匹配任意数量的字母数字字符。

Answer 3

查看添加的示例后，知道 OP 不想捕获任何内容，让我们将其简化为：

www\.mysite\.com\/(?:abc|def|something\/thisone(?:\/[^\/\s]+)+)\/?

解释：

www\.mysite\.com         # match www.mysite.com
\/                       # followed by `/`
(?:                      # non-capturing group 1
  abc                    # 'abc'
  |                      # OR
  def                    # 'def'
  |                      # OR
  something\/thisone     # 'something/thisone' followed by
  (?:                    # non-capturing group 2
    \/                   # '/' 
    [^\/\s]+             # 1 or more chars, not '/' or space
  )+                     # END group 2. 1 or more times.
)                        # END group 1
\/?                      # optional closing /

例如：regex101