【发布时间】:2014-08-16 16:47:52
【问题描述】:
我正在尝试将第一个可用选项加载到第三个下拉列表中。
代码如下。
var categories = [];
categories["startList"] = ["C.","C#.","D.","Eb.","E.","F.","F#.","G.","Ab.","A.","Bb.","B."]; // Level 1
categories["C."] = ["C","C7","Cm","Cm7","Cmaj7","Csus4","Caug","Cdim"];
categories["C"] = ["032010","335553","133211","543210",""];
var nLists = 3; // number of lists in the set
function fillSelect(currCat,currList){
var step = Number(currList.name.replace(/\D/g,""));
for (i=step; i<nLists+1; i++) {
document.forms[0]['List'+i].length = 1;
document.forms[0]['List'+i].selectedIndex = 0;
}
var nCat = categories[currCat];
for (each in nCat) {
var nOption = document.createElement('option');
var nData = document.createTextNode(nCat[each]);
nOption.setAttribute('value',nCat[each]);
nOption.appendChild(nData);
currList.appendChild(nOption);
}
}
function init() { fillSelect('startList',document.forms[0]['List1']);
fillSelect('startList',document.forms[0]['List4']);
fillSelect('startList',document.forms[0]['List7']);
}
navigator.appName == "Microsoft Internet Explorer"
? attachEvent('onload', init, false)
: addEventListener('load', init, false);
function getValues() {
var str = '';
for(i = 1; i < 6; i++) {
document.createElement('select')
str += document.getElementById('List' + i).value+'\n';
document.getElementById('creation').innerHTML=""; }
}
<select name='List4' id="List4" onchange="fillSelect(this.value,this.form['ch2'])"><option selected></option></select>
<select name='ch2' id="ch2" onchange="fillSelect(this.value,this.form['tb2'])"><option selected></option></select>
<select name='tb2' id="tb2"><option selected></option></select>
<input id="f2" type="text" size="1" value=1 class=copystuff>
<button onclick="do2()">Do2</button><br>
现在的问题是,当我尝试选择第二个下拉菜单“ch2”时,我希望根据我在第二个菜单中所做的选择,在第三个下拉菜单“tb2”中自动加载第一个值。例如,如果我在第一个菜单中选择 C.,在第二个菜单中选择 C,我希望在下一个菜单中已经选择了 032010。有什么简单的方法可以做到这一点吗?
【问题讨论】:
-
你能附上一个 jsFiddle 吗?
标签: javascript html drop-down-menu